#include<stdio.h>

int main(void)
{
char text1[]="I'm a big man. ";
char text2[]="in this little. ";
int countWords(char string[]);

printf("%s-wordsnumber=%i\n", text1, countWords(text1) );
printf("%s-wordsnumber=%i\n", text2, countWords(text2) );
return 0;
}


int alphabetic(char c)
{
if( (c>='a' && c<='z')||(c>='A' && c<='Z') )
  return 1;
else return 0;
}


int countWords(char string[])
{
int alphabetic(char c), i, wordcount=0,
                  lookingforword=1;

for(i=0; string[i]!='\0'; i++)
{
    if(alphabetic(string[i]) )
    {
        if(lookingforword=1)
        {
            wordcount++;
            lookingforword=0;
        }else lookingforword=0;
        
    }else lookingforword=1;
    }
    return wordcount;
}


到i=6的时候， lookingforword=0了，i=7的时候， 电脑又跟我把它还原成1，
不知道如何是好啊！

功能是计算text1, text2的单词数目。