#include "stdio.h"
#include "iostream.h"
#include "string.h"

char* GetTablename(char *FilePath, char *TableName)
{
FILE *fp1;
char line[100];
char *p;
bool bol = false;

fp1 = fopen( FilePath, "r" );
while(!feof(fp1))
{
if( fgets( line, 100, fp1 ) == NULL)
return NULL;

p = strtok(line, " ");
if (strcmp(p, TableName) == 0)
{
bol = true;
}

p = strtok(NULL, " ");
if(bol)
{
return p;
}

}
fclose(fp1);

return NULL;
}

void main()
{
char *q;

q = GetTablename( "D:\\111.txt", "tablename1");

cout<< q << endl;
}

输出是9@
应该是aaa 啊

D:\\111.txt
tablename1 aaa
tablename2 bbb

改变了下TXT的数,还是错的

读每一行文件啊,,
这里是要传2个参数,一个是英文名,要返回是表中文名,

错误找到了,因为返回的是指针,前面涵数完了,指针指向的地址也清掉了,所以最后打出来的是乱码.
把返回的P指针对应的地址LINE变成公共变量就行.


#include "stdio.h"
#include "iostream.h"
#include "string.h"

char* GetTablename(char *FilePath, char *TableName, char *line)
{
FILE *fp1;
char *p;
bool bol = false;

if ((fp1 = fopen( FilePath, "rt" )) == NULL)
{
return NULL;
}

fp1 = fopen( FilePath, "r" );

while(!feof(fp1))
{
if( fgets( line, 100, fp1 ) == NULL)
return NULL;

p = strtok(line, " ");
if (strcmp(p, TableName) == 0)
{
bol = true;
}

p = strtok(NULL, " ");
if(bol)
{
cout<< p << endl;
return p;
}

}
fclose(fp1);

return NULL;
}

void main()
{
char *q;
char line[100];
q = GetTablename( "D:\\111.txt", "t2", line);
if(q != NULL)
{
cout<< q << endl;
}
}