帮我看道题好吗

先申请一个内存空间放下二维数组，然后找到只出现一次的行
代码如下，不知怎么修改
clude <stdio.h>
#include <malloc.h>
#include <stdlib.h>
#define N 7
#define M 3
int check(int *p,int *q,int length);
int main(void)
{
int i, j;
int *p=(int *)malloc(60);
p=&a;
int a[N][M]={{1,2,3},{2,5,6},{1,2,3},{3,6,9},{3,4,7},{1,2,3},{3,4,7}};
for (i=0; i<N; i++)
{
for (j=0; j<N; j++)
{
if (j==i) continue;
if (check(a[i], a[j], M)) goto NEXT;
}
printf("%3d:\t",i+1);
for (j=0; j<M; j++)
printf("%d ",a[i][j]);
printf("\n");
NEXT:;
}
return 0;
free(p);
}
int check(int *p, int *q, int length)
{
int i=0;
for (; i<length; i++)
if (p[i]!=q[i])
return 0;
return 1;
}

错在内存申请那块儿了，不知怎么改，请达人指点

哦，不好意思，确实是粘贴的时候反了，
#include <stdio.h>
#include <malloc.h>
#include <stdlib.h>
#define N 7
#define M 3
int check(int *p,int *q,int length);
int main(void)
{
int i, j;
int *p=(int *)malloc(10*sizeof(int));

int a[N][M]={{1,2,3},{2,5,6},{1,2,3},{3,6,9},{3,4,7},{1,2,3},{3,4,7}};
p=&a;
for (i=0; i<N; i++)
{
for (j=0; j<N; j++)
{
if (j==i) continue;
if (check(a[i], a[j], M)) goto NEXT;
}
printf("%3d:\t",i+1);
for (j=0; j<M; j++)
printf("%d ",a[i][j]);
printf("\n");
NEXT:;
}
return 0;
free(p);
}
int check(int *p, int *q, int length)
{
int i=0;
for (; i<length; i++)
if (p[i]!=q[i])
return 0;
return 1;
}
运行后总是提示、：warning C4047:“=”：“int *”differs in
levels of indirection from “int （*）[7][3]”
什么意思啊