#include "stdio.h"
main()
{

char str[81];
int i,num=0,word=0;
char c;
gets(str);
for(i=0;(c=str[i])!='\0';i++)
if(c=='')word=0;
else if(word==0)
{
word=1;
num++;
}
printf("there are %d word in the line\n",num);

}

比如我输入:i am a boy
输出应当是:thera are 4 words in the line
可这段程序输出的是: there are 1 words in the line

if (c=='')word=0;
我想表示当前字符是空格,word的值为0;

1.刚学,有时候处理问题老是一根筋.多谢美女批评指正.
2.已通过测试.再次感谢.
3.还有谢谢楼上提议,我努力改正.