用fork( )创建两个子进程，再用系统调用signal( )让父进程捕捉键盘上来的中断信号（即按^c键）；捕捉到中断信号后，父进程用系统调用kill( )向两个子进程发出信号，子进程捕捉到信号后分别输出下列信息后终止：
Child process1 is killed by parent!
Child process2 is killed by parent!
父进程等待两个子进程终止后，输出如下的信息后终止：
Parent process is killed!



#include <stdio.h>
#include <signal.h>
#include <unistd.h>

void waiting( ),stop( );
int wait_mark;
main( )
{
int p1,p2,stdout;
while((p1=fork( ))= =-1); /*创建子进程p1*/
if (p1>0)
{
while((p2=fork( ))= =-1); /*创建子进程p2*/
if(p2>0)
{
wait_mark=1;
signal(SIGINT,stop); /*接收到^c信号，转stop*/
waiting( );
kill(p1,16); /*向p1发软中断信号16*/
kill(p2,17); /*向p2发软中断信号17*/
wait(0); /*同步*/
wait(0);
printf("Parent process is killed!\n");
exit(0);
}
else
{
wait_mark=1;
signal(17,stop); /*接收到软中断信号17，转stop*/
waiting( );
lockf(stdout,1,0);
printf("Child process 2 is killed by parent!\n");
lockf(stdout,0,0);
exit(0);
}
}
else
{
wait_mark=1;
signal(16,stop); /*接收到软中断信号16，转stop*/
waiting( );
lockf(stdout,1,0);
printf("Child process 1 is killed by parent!\n");
lockf(stdout,0,0);
exit(0);
}
}

void waiting( )
{
while(wait_mark!=0);
}

void stop( )
{
wait_mark=0;
}

、运行结果
屏幕上无反应，按下^C后，显示 Parent process is killed!

1.为何预期的结果并未显示出？
2.程序该如何修改才能得到正确结果？
3.不修改程序如何得到期望的输出？