int sum(int x,int y)
{ int z;
if(y=1) z=1;
else z=sum(x-1,y-1)+y;
return(z);
}

main()
{
int s,n,i;
scanf("%d,%d",&n,&i);
printf("%d",sum(int n,int i));

}

递归 求 1+2+3+ ~ ~ ~ +100的和 if(y=1) z=1; 总是这一句有问题

int sum(int x,int y)
{ int z;
if(y==1) z=1;
else z=sum(x-1,y-1)+y;
return(z);
}

main()
{
int s,n,i;
scanf("%d,%d",&n,&i);
printf("%d",sum(n,i));

} 这样吧 ? 刚刚自己在看了下