i=4,p = (++i) + (i++) + (i++);语句的结果为啥是17?汇编代码分析如何与源代码对应？
程序代码：
void f05_1(){
int p = 0, i = 4;
p = (++i) + (i++) + (i++);
printf("p = %d,i = %d\n", p, i);
}
程序代码：
f05_1:
.LFB10:
.cfi_startproc
endbr64
pushq %rbp
.cfi_def_cfa_offset 16
.cfi_offset 6, -16
movq %rsp, %rbp
.cfi_def_cfa_register 6
subq $16, %rsp
movl $0, -8(%rbp)
movl $4, -4(%rbp)
addl $1, -4(%rbp)
movl -4(%rbp), %eax
leal 1(%rax), %edx
movl %edx, -4(%rbp)
movl -4(%rbp), %edx
leal (%rax,%rdx), %ecx
movl -4(%rbp), %eax
leal 1(%rax), %edx
movl %edx, -4(%rbp)
addl %ecx, %eax
movl %eax, -8(%rbp)
movl -4(%rbp), %edx
movl -8(%rbp), %eax
movl %eax, %esi
leaq .LC0(%rip), %rdi
movl $0, %eax
call printf@PLT
nop
leave
.cfi_def_cfa 7, 8
ret
.cfi_endproc
.LFE10:
.size f05_1, .-f05_1
.globl f05_2
.type f05_2, @function
汇编代码中第十二句的
movl -4(%rbp), %eax
是对应C语言表达式中的保存第一个(i++)的值吗
