#include <iostream>
#include <string>
using namespace std;
class person
{
public:
string name;
person *Rlink;
// person *Llink;
};
void main()
{
person *first=NULL;
person *last=NULL;
person *current=NULL;

person *newnode=NULL;

newnode=new person;
newnode->name="a";
newnode->Rlink=NULL;
first=last=newnode;
for(int i=0;i<5;i++)
{
newnode=new person;
newnode->name="a";
newnode->Rlink=NULL;

last->Rlink=newnode;
last=newnode;
}
for(current=first;current->name!="c"&&current!=NULL; //注意这一行,这一行的"C"改成"a"就错了,为什么
current=current->Rlink);
if(current==NULL)
{
cout<<"没有要找的数";
}
else
{
cout<<current->name;
}
}

先谢了,
不过好像要查找NAME为C的还是会出错啊
我知道一种方法,改成如下就行了,但是为什么呢?
#include <iostream>
#include <string>
using namespace std;

class person
{
public:
string name;
person * Rlink;
};

int main()
{
person * first = NULL;
person * last = NULL;
person * current = NULL;

person * newnode = NULL;

newnode = new person;
newnode->name = "a";
newnode->Rlink = NULL;
first = last = newnode;

for(int i=0;i<5;i++)
{
newnode=new person;
newnode->name="a";
newnode->Rlink=NULL;

last->Rlink=newnode;
last=newnode;
}

bool same=false; //改的这里
for(current=first; !same && current!=NULL;
current=current->Rlink)
{
if(current->name=="c")
same=true;
}

if(current==NULL)
{
cout<<"not found";
}
else
{
cout<<current->name;
}
}