/*百元买百鸡，公鸡2元，母鸡1元，小鸡0.5元，正好要买100只鸡有几种做法*/
哪位高收给点思路,用循环做!

main( )
{
int cocks,hens,chicks;
cocks=0;
while(cocks<100/2)
{
hens=0;
while(hens<100/1)
{
chicks=100-cocks-hens;
if(2*cocks+hens+chicks/2==100&&chicks%2==0)
printf("%d,%d,%d\n",cocks,hens,chicks);
hens=hens+1;
}

/*
1,97,2
2,94,4
3,91,6
4,88,8
5,85,10
6,82,12
7,79,14
8,76,16
9,73,18
10,70,20
11,67,22
12,64,24
13,61,26
14,58,28
15,55,30
16,52,32
17,49,34
18,46,36
19,43,38
20,40,40
21,37,42
22,34,44
23,31,46
24,28,48
25,25,50
26,22,52
27,19,54
28,16,56
29,13,58
30,10,60
31,7,62
32,4,64
33,1,66

*/
cocks=cocks+1;
}
}

main()
{
int cock,hen,chick;
for(cock=1;cock<50;cock++)
for(hen=1,chick=99-cock;hen<97;hen++)
if(2*cock+1*hen+0.5*chick==100)
printf("cock=%d;hen=%d;cock=%d\n",cock,hen,chick);
}

还有其他得几种方法，不过都是这个得变通！你自己变变吧！