# include <iostream.h>
#include <string.h>

struct students {
char num [6];
char name [10];
int greag ;
};

students a[4]=
{
{"af321" , "周润法" , 78 }, {"ad321" , "水均益" , 93 },
{"aa321" , "张朝阳" , 85 }, {"ag321" , "刘翔" , 75 }
};

int search(students s[],int n, students x)//输入一个人名则显示其存在与否!
{
for(int i=0;i<n;i++)
{
if(strcmp(s[i].name,x.name)==0)
return i;
return -1;
}
}

void main()
{
int m=4;
students one_person_name[]="刘翔";//*one_person_name="刘翔";也输不过去!
//如何能将要查找的"人名"作为参数传递到search函数中去??
search(a,m,one_person_name);
}

one_person_name类型不应该是students而应该是strin个或者char *...

void main()
{
int m=4;
students one_person_name={"","刘翔",0};
search(a,m,one_person_name);
}

程序改成这样就可以啦
#include <iostream>
#include <string>
using namespace std;
struct students {
char num [6];
char* name ;
int greag ;
};

students a[4]=
{
{"af321" , "周润法" , 78 }, {"ad321" , "水均益" , 93 },
{"aa321" , "张朝阳" , 85 }, {"ag321" , "刘翔" , 75 }
};

int search(students *s,int n, students x)
{
for(int i=0;i<n;i++)
{
if(strcmp(s[i].name,x.name)==0)
return i;
else
return -1;
}

}

void main()
{
int m=4;
students oneperson;
oneperson.name="刘翔";

cout<<search(a,m,oneperson);
}

E:\C++指针\hhhh\fd.cpp(31) : error C2440: '=' : cannot convert from 'char [5]' to 'char [10]'
There is no context in which this conversion is possible
Error executing cl.exe.

hhhh.exe - 1 error(s), 0 warning(s)

试试我说的看行不行

[此贴子已经被作者于2006-8-29 13:24:09编辑过]

改成strcpy(oneperson.name,"刘翔");
int search(students *s,int n, students x)
{
for(int i=0;i<n;i++)
{
if(strcmp(s[i].name,x.name)==0)
return i;
else
return -1;
}

}

是错误的，第一元素如果不是所找的元素，就返回-1！！
return -1；应放在最后。

strcpy(oneperson.name,"刘翔");这应该是不行的

你见过
char*name;
strcpy(name,"刘翔");
没？

没分配内存吧。



但是可以:
char*name;
name="刘翔";

int search(students *s,int n, students x)
{
for(int i=0;i<n;i++)
{
if(strcmp(s[i].name,x.name)==0)
return i;
else
return -1;
}

}

是错误的，第一元素如果不是所找的元素，就返回-1.
应该改成:

int search(students *s,int n, students x)
{
for(int i=0;i<n;i++)
if(strcmp(s[i].name,x.name)==0)
return i;
else
return -1;

}