你不给我看你的web.xml和dodoFilter代码,我想帮也帮不了呀

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd">
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>

<filter>
<filter-name>Message Board Authority Filter</filter-name>
<filter-class>AuthorityFilter</filter-class>
<init-param>
<param-name>login</param-name>
<param-value>login.jsp</param-value>
</init-param>
<init-param>
<param-name>notlogin</param-name>
<param-value>login</param-value>
</init-param>
</filter>
<filter-mapping>
<filter-name>Message Board Authority Filter</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>

</web-app>


doFilter()

import javax.servlet.*;
import javax.servlet.http.*;
import java.io.IOException;

import pub.util.*;

public class AuthorityFilter implements Filter
{
FilterConfig filterConfig = null;
String login = "login.jsp";
String[] nologin = null;

// 读取初始化配置参数
public void init(FilterConfig config) throws ServletException
{
this.filterConfig = config;

// 读取登录页面连接（在用户没有登录的时候会跳转到该页面）
String login = filterConfig.getInitParameter( "login" );
this.login = login;

// 读取不需要登录的连接
String notlogin = filterConfig.getInitParameter( "notlogin" );
this.nologin = StringUtil.strTokenizer( notlogin, "," );
}

// 处理操作
public void doFilter( ServletRequest request,
ServletResponse response,
FilterChain chain )
throws IOException, ServletException
{
HttpServletRequest req = (HttpServletRequest)request;
HttpServletResponse res = (HttpServletResponse)response;

// 判断当前请求是否为不需要登录的请求
if( this.nologin!=null )
{
String requri = req.getRequestURI();
for( int i=0; i<nologin.length; i++ )
{
if( requri.indexOf( nologin[i] ) > 0 )
{
chain.doFilter( request, response );
return;
}
}
}

RequestDispatcher dispatcher = req.getRequestDispatcher( login );
dispatcher.forward( request, response );
}

public void destroy()
{
this.filterConfig = null;
this.nologin = null;
}
}


这个函数是没有问题的StringUtil.strTokenizer( notlogin, "," )

不管我的路径是什么，都可以通过，这个doFilter()好像没有起到作用

[此贴子已经被作者于2006-8-19 12:46:56编辑过]