假如现在已经打开exe文件了,如果再次双击,将会再打开一个新的,如果避免这种情况?
当有一个实例在运行时,再打开一个的话将其直接终止,这应该如何做呢?
请高手指点指点
判斷是否有該應用程序的實例存在
using System;
using System.Runtime.InteropServices;
using System.Windows.Forms;
using System.Diagnostics;
using System.Reflection;
public class OneInstnace
{
[STAThread]
public static void Main()
{
//Get the running instance.
Process instance = RunningInstance();
if (instance == null)
{
//There isn't another instance, show our form.
Application.Run (new Form());
}
else
{
//There is another instance of this process.
HandleRunningInstance(instance);
}
}
public static Process RunningInstance()
{
Process current = Process.GetCurrentProcess();
Process[] processes = Process.GetProcessesByName (current.ProcessName);
//Loop through the running processes in with the same name
foreach (Process process in processes)
{
//Ignore the current process
if (process.Id != current.Id)
{
//Make sure that the process is running from the exe file.
if (Assembly.GetExecutingAssembly().Location.Replace("/", "\\") ==
current.MainModule.FileName)
{
//Return the other process instance.
return process;
}
}
}
//No other instance was found, return null.
return null;
}
public static void HandleRunningInstance(Process instance)
{
//Make sure the window is not minimized or maximized
ShowWindowAsync (instance.MainWindowHandle , WS_SHOWNORMAL);
//Set the real intance to foreground window
SetForegroundWindow (instance.MainWindowHandle);
}
[DllImport("User32.dll")]
private static extern bool ShowWindowAsync(
IntPtr hWnd, int cmdShow);
[DllImport("User32.dll")] private static extern bool
SetForegroundWindow(IntPtr hWnd);
private const int WS_SHOWNORMAL = 1;
}