如题谢谢.

通过判断TreeNode对象的Parent属性是否为null

int intLayerCount = 1;
TreeNode treeNodeTemp = treeNodeSelected; //假定treeNodeSelected为当前选择的节点
while (treeNodeTemp.Parent != null)
{
intLayerCount++;

treeNodeTemp = treeNodeTemp.Parent;

}

还是没判断出来呀.

老帖子啦啊哈..
顶一哈

我想得到所有节点的数目..给怎么办?
递归吗?
怎么递?又怎么归?

private int getlev(TreeNode tn) //计算当前选中节点所在层数
{

if (tn.Parent != null) //当前节点有父节点
{
return node_level + getlev(tn.Parent) + 1;
}
else
return 1;
}

private void button1_Click(object sender, EventArgs e)
{
int i= this.treeView1.Nodes.Count;
foreach (TreeNode t in this.treeView1.Nodes)
{
count = count + 1;
getNode(t,false);
}
this.button1.Text = count.ToString();
}
private void getNode(TreeNode t,bool b)
{
if (b)
{
count = count + 1;
}
for(int i=0;i<t.Nodes.Count;i++)
{

getNode(t.Nodes[i],true);
}
}
所有節點遞歸

hhe  .wo  ye  zhidao a

TreeNode的Level

this.treeview.SelectedNode.Level