请教char *的问题
我想将两char *的值相加并赋给char *返回值
char * rxg(char * a,char *b)
{
size_t n=strlen(a)+strlen(b)+1;
char * c=new char[n];
strcpy_s(c,n,a);
strcat_s(c,n,b);
return c;
}

这样写会产生一个new内存空间,返回后没有办法delete c这个空间

有没有好的方法,将两char *类型的值相加并返回给char *类型

谢谢:)

try it:
#include <iostream>
#include <string>
using namespace std;
char * rxg(char * a,char *b)
{
size_t n=strlen(a)+strlen(b)+1;
char * c=new char[n];
strcpy(c,a);
strcat(c,b);
return c;
}
int main()
{
char a[] = "love ";
char b[] = "C++!";
char * c = a;
char * d = b;
char * e = rxg(c,d);
cout<<e<<endl;
delete[]e;
return 0;
}

谢谢:)

[CODE]

#include <iostream>
#include <cstdlib>
#include <cstring>
using namespace std;

char * rxg(char * c, int cSize, const char * a, const char * b)
{
  if(a != NULL && b != NULL)
  {
    strncpy(c, a, cSize-1);
		c[cSize-1] = '\0';
    unsigned int cRemaining = (cSize - strlen(c)) - 1;
		strncat(c, b, cRemaining);
	  return c;
  }
	return NULL;
}

int main()
{
  char a[] = "love ";
  char b[] = "C++!";
  char c[10];
  
	int csize = sizeof(c);
	
	rxg(c, csize, a, b);
	cout<<c<<endl;
  system("pause");	
  return 0;
}

[/CODE]

谢谢:)