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#include <stdio.h>
#include <stdbool.h>

long get_long(void);
bool bad_limits(long begin, long end, long low, long high);
double sum_squares(long a, long b);

int main(void) {
const long MIN = -10000000L;
const long MAX = +10000000L;
long start;
long stop;

printf("This program computes the sum of the squares of"
"integers in a range.\nThe lower bound should not"
"be less than -10000000 and\nthe upper bound"
"should not be more than +10000000.\nEnter the"
"limits (enter 0 for both limits to quit);\n"
"lower limit: ");
start = get_long();
printf("upper limit: ");
stop = get_long();
while (start != 0 || stop != 0) {
else {
printf("The sum of the square of the integers ");
printf("from %ld to %ld is %g\n", start, stop, answer);
}
printf("Enter the limits(enter 0 for both limits to quit):\n");
printf("lower limit: ");
start = get_long();
printf("upper limit: ");
stop = get_long();
}
printf("Done!.\n");
return 0;
}

long get_long(void) {
long input;
char ch;

while (scanf("%ld", &input) != 1) {
while ((ch = getchar()) != '\n')
putchar(ch);
printf(" is not an integer.\nplease enter an ");
printf("integer value,such as 25,-178,or 3: ");
}
return input;
}

bool bad_limits(long begin, long end, long low, long high) {
bool not_good = false;
if (begin > end) {
printf("%ld isn't smaller than %ld .\n", begin, end);
not_good = true;
}
if (begin < low || end < low) {
printf("Values must be %ld or greater.\n", low);
not_good = true;
}
if (begin > high || end > high) {
printf("Values must be %ld or less", high);
not_good = true;
}
return not_good;
}

double sum_squares(long a, long b) {
double total = 0;
long i;

for (i = a; i <= b; i++)
total += (double)i * (double)i;

}

[此贴子已经被作者于2022-4-20 18:40编辑过]

-10000000L到+10000000L的平方和 = 2 * 10000000*(10000000+1)*(2*10000000+1)/6 = 666666766666670000000
ln(666666766666670000000)/ln(2) = 70bits

double占用64bits，有效位只有53bits

1bit的符号位，11bits的阶码，隐含的1.不占空间，52bits的尾数

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