在保存字符串时，对出现在连续位置的若干个字符，如这些字符在ASCII表中也是连续出现，则可以将这些字符使用缩写形式进行保存，以节省保存空间。例如用A-Z表示ABCDEFGHIJKLMNOPQRSTUVWXYZ，1-5表示12345，c-f表示cdef。
【要求】用指针完成
输入：包含缩写形式的字符串
输出：将缩写形式进行还原后的字符串
说明：只处理大小写字母和数字，即对于形如A-9，a-C这样的缩写不进行处理

测试用例1
输入：0-9
输出：0123456789

测试用例2
输入：a-z
输出：abcdefghijklmnopqrstuvwxyz

测试用例3
输入：G-I
输出：GHI

测试用例4
输入：ABDG-K035-9abd-h
输出：ABDGHIJK0356789abdefgh

#include <conio.h>
void main() 
{
    int map[] = {0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0};
    char prev, cur, next;

    prev = 0;
    while (1)
    {
        cur = getchar();
        if (cur == '-')
        {
            next = getchar();
            if (map[prev] && map[next] && ((prev^next)<' ') && prev+1<next)
            {
                while (prev+1 < next)
                {
                    prev++;
                    printf("%c", prev);
                }
            }
            else
            {
                printf("%c", cur);
            }
            cur = next;
        }
        
        printf("%c", cur);

        if (cur == '\n')
        {
            break;
        }

        prev = cur;
    }
}