#include<stdio.h>

int main()
{
    int i, j, count=0;
    for(i=1;i<=10;i++){
        for(j=1;j<=10;j++){
            count++;                            我想问一下这个count在这块是什么意思，以及有什么作用
            printf("%4d",count);               
        }
        printf("\n");
    }
    return 0;
}

要实现输出1-100的数，所以count从1开始递增并输出

#include<stdio.h>

int main()
{
    int i, j, count=0;
    for(i=1;i<=10;i++){ //外层循环10次 
        for(j=1;j<=10;j++){ //内层循环10次 总共循环100次 
            count++;              // count从0开始 每循环一次+1 
            printf("%4d",count);               //以4宽度 输出 1~100 
        }
        printf("\n"); //每循环10次打印一次换行 
    }
    return 0;
}

count 就是你要的数字 1 2 3 4 5 6.。。

#include<stdio.h>
int main()
{
    int i,count = 0;
    for(i=0;i<100;i++)
    {
        if(i%10==0) printf("\n");
        count++;
        printf("%6d",count);
    }
     return 0;
}

//online parser: https://www.bccn.net/run/

#include <stdio.h>

typedef unsigned char uint8_t;
typedef signed char int8_t;
#define OPCODE_JMP 0xE9
//D7D6     D5D4     D3D2D1  D0    
//11       10       100     1
#define TST_MSB(_op)  (int8_t)((_op & 0x0f) << 4)
#define TST_LSB(_op)  (_op & 0x01)
#define TST_RE(_op)   (int8_t)(_op << 2)
#define TST_FS(_op)   (int8_t)(_op)

int main(int argc, char *argv[])
{
    int i = 0, count = 0, re = 0;
    char s[] = "%0d";
    
    if(TST_MSB(OPCODE_JMP) < 0) count += 100;
    if(TST_MSB(OPCODE_JMP << 1) < 0) count += 10;
    if(TST_MSB(OPCODE_JMP << 2) < 0) count += 1;
    if(TST_RE(OPCODE_JMP) < 0) re += 10;
    if(TST_RE(OPCODE_JMP << 1) < 0) re += 1;
    if(TST_FS(OPCODE_JMP) < 0) s[1] += 4;
    if(TST_FS(OPCODE_JMP << 1) < 0) s[1] += 2;
    
    for(i = TST_LSB(OPCODE_JMP) - 1; i < count; i++) {
        if(i % re == 0) printf("\n"); printf(s, i + 1);
    }

    return 0;
}

bit data just for funny

//online parser: https://www.bccn.net/run/

#include <stdio.h>

typedef unsigned char uint8_t;
typedef signed char int8_t;
#define OPCODE_JMP 0xE9
//FS       RE       COUNT   HEAD
//D7D6     D5D4     D3D2D1  D0    
//11       10       100     1
uint8_t dmap[] = {
    1, 10, 6, 100, '%', '0', 'd'
};
#define _B2D(_b)      dmap[_b - 1]
#define HEAD(_op)     (uint8_t)(_op & 0x01)
#define COUNT(_op)    _B2D(((_op & 0x0f) >> 1))
#define RE(_op)       _B2D(((_op & 0x30) >> 4))
#define FS(_op)       _B2D(((_op & 0xc0) >> 6)) + 0x30
#define MAKEWORD(_h, _l) (_h << 8 | _l)
#define MAKEDWORD(_H, _L) (_H << 16 | _L)
int parse_cmd(uint8_t c)
{
    int pvs;
    pvs = MAKEDWORD(MAKEWORD(FS(c), RE(c)), MAKEWORD(COUNT(c), (HEAD(c) - 1)));

    return pvs;
}

int main(int argc, char *argv[])
{
    int i, pvs;

    pvs = parse_cmd(OPCODE_JMP);
#define CASTU8(_int) ((uint8_t *)&_int)
enum PVS {
    HD = 0, CNT, RE, FS
};    
    for(dmap[5] = CASTU8(pvs)[FS], i = CASTU8(pvs)[HD]; 
        i < CASTU8(pvs)[CNT]; i++) {
        if(0 == i % CASTU8(pvs)[RE]) printf("\n"); 
        printf((char *)&dmap[4], i + 1);
    }
    
    return 0;
}

//online parser: https://www.bccn.net/run/

#include <stdio.h>

typedef unsigned char uint8_t;
typedef signed char int8_t;
#define OPCODE_JMP 0xE9
//define usr protocol bit
//FS       RE       COUNT   HEAD
//D7D6     D5D4     D3D2D1  D0    
//11       10       100     1
enum PVS {
    PHD = 0, CNT, REV, FST, STR
};
uint8_t dmap[][8] = {
#define UN_USED 255
    {0, 1, UN_USED, UN_USED, UN_USED, UN_USED, UN_USED, UN_USED},
    {0, 1, 10, 11, 100, 101, 110, 111},
    {10, 10, 10, 11, UN_USED, UN_USED, UN_USED, UN_USED},
    {0, 2, 4, 6, UN_USED, UN_USED, UN_USED, UN_USED},
    {'%', '0', 'd', 0, UN_USED, UN_USED, UN_USED, UN_USED}
};
#define _B2D(_r, _b)  dmap[_r][_b]
#define PHD(_op)     _B2D(PHD, (uint8_t)(_op & 0x01))       //0/1
#define CNT(_op)     _B2D(CNT, ((_op & 0x0f) >> 1))         //000-111
#define REV(_op)     _B2D(REV, ((_op & 0x30) >> 4))         //00-11
#define FST(_op)     _B2D(FST, ((_op & 0xc0) >> 6)) + 0x30  //00-11
#define MAKEWORD(_h, _l) (_h << 8 | _l)
#define MAKEDWORD(_H, _L) (_H << 16 | _L)
int parse_cmd(uint8_t c)
{
    int pvs, i;
    pvs = MAKEDWORD(MAKEWORD(FST(c), REV(c)), 
    MAKEWORD(CNT(c), (PHD(c))));
    
#define CASTU8(_int) ((uint8_t *)&_int)
    for(dmap[STR][1] = CASTU8(pvs)[FST], i = CASTU8(pvs)[PHD]; 
        i <= CASTU8(pvs)[CNT]; i++) {
        printf(CASTU8(dmap[STR]), i);
        if(0 == i % CASTU8(pvs)[REV]) printf("\n"); 
    }
    
    return pvs;
}

int main(int argc, char *argv[])
{
    int pvs, i;
    uint8_t *p;
    double pi = 3.1415926;

    //test pi
    for(p = (uint8_t *)&pi, i = 0; i < sizeof(double); i++) {
        printf("[%d:]0x%x\n", i + 1, p[i]);
        parse_cmd(p[i]);
    }
    //end of OPCODE_JMP
    parse_cmd(OPCODE_JMP);
    
    return 0;
}

[此贴子已经被作者于2021-9-1 22:46编辑过]