struct ele {
    int no;
    struct ele *link;
}

h = u = (struct ele *)malloc(sizeof(struct ele));/*形成首表元*/
    h->no = 1;
    for (i = 2; i <= n; i++)/*形成其余的n-1个表元*/
    {
        u->link = (struct ele *)malloc(sizeof(struct ele));  //？？？此步如何将h->link指向u?????
        u = u->link;
        u->no = i;/*第i个表元置编号i*/
    }
    u->link = h;/*末表元后继首表元，形成环*/

此步是如何将h->link指向u的?
前者求的是方法步骤，后者问的结果原因。

答：因为一开始时 h = u