运行后会导出一个xls表格，但是打开表格后里面是错误信息，实在不会排查错误，请大神帮忙看看
Notice: Undefined variable: goods_name in D:\phpStudy\WWW\db.php on line 38            
Notice: Undefined variable: gongjinjia in D:\phpStudy\WWW\db.php on line 39            
Notice: Undefined variable: xinghao in D:\phpStudy\WWW\db.php on line 40            
Notice: Undefined variable: caizhi in D:\phpStudy\WWW\db.php on line 41            


<?php
    error_reporting(E_ALL ^ E_DEPRECATED);
    $localhost = '127.0.0.1';
    $dbname = 'test';
    $dbuser = 'root';
    $dbpwd = 'root';
    $tbname = "yz_info";

    ob_end_clean();
    header('Content-type: text/html; charset=utf-8');
    header("Content-type:application/vnd.ms-excel;charset=UTF-8");
    header("Content-Disposition:filename=data.xls");// 文件名自己改，默认data.xls

    $conn = mysql_connect($localhost,$dbuser,$dbpwd) or die("连接数据库失败");
    mysql_select_db($dbname, $conn);
    mysql_query("set names 'UTF-8'");

    $result=mysql_query("SELECT * FROM $tbname");
    echo "<table>";
    echo "<tr>";
    echo "<th>A1单元格</th>";
    echo "<th>B1单元格</th>";
    echo "<th>C1单元格</th>";
    echo "<th>D1单元格</th>";
    echo "</tr>";
    echo "</table>";
    while($row=mysql_fetch_array($result)){
        //下面data改成你自己数据库对应的字段
        $data1 = $row["goods_name"];
        $data2 = $row["gongjinjia"];
        $data3 = $row["xinghao"];
        $data4 = $row["caizhi"];
        
        //输出字段的数据到单元格
        //下面data改成你自己数据库对应的字段
        echo "<table>";
        echo "<tr>";
            echo "<td>$goods_name</td>";
            echo "<td>$gongjinjia</td>";
            echo "<td>$xinghao</td>";
            echo "<td>$caizhi</td>";
        echo "</tr>";
        echo "</table>";
    }
?>

//下面data改成你自己数据库对应的字段
        echo "<table>";
        echo "<tr>";
            echo "<td>$goods_name</td>";
            echo "<td>$gongjinjia</td>";
            echo "<td>$xinghao</td>";
            echo "<td>$caizhi</td>";

写得很明白，这4个变量没定义，你上面用的是$data1-$data4，这里又用这个变量名，这2处改成一样

谢谢您，确实是这里错了，改完后可以正常运行，非常感谢