第一种方法直接让指针q指向指针p，从而让指针q获取指针p所指向字符串的值，代码如下：

#include"stdio.h"
void strcpy(char *q[],char *p[],int n){
    int i;
    int j,m;
    for(i=0;i<n;i++)
        q[i]=p[i];
    for(j=0;j<n;j++)
        printf("%s ",q[j]);
}
int main(void){
    char *p[5]={"asdg","uewnngn","sngn","fhh","mngkkd"};
    char *q[5];
    strcpy(q,p,5);
    return 0;
}

第二种方法将指针p所指向字符的值一个一个拷贝给指针q.但却无法运行，是什么原因？代码如下：

#include"stdio.h"
void strcpy(char *q[],char *p[],int n){
    int i;
    int j,m;
    for(i=0;i<n;i++)
        for(m=0;m<100&&*(p[i]+m);m++)
            *(q[i]+m)=*(p[i]+m);
    for(j=0;j<n;j++)
        printf("%s ",q[j]);
}
int main(void){
    char *p[5]={"asdg","uewnngn","sngn","fhh","mngkkd"};
    char *q[5];
    strcpy(q,p,5);
    return 0;
}

[此贴子已经被作者于2020-5-11 02:47编辑过]

因为q没有指向的目标 ，  可以先指向，也可以赋值的时候自己malloc

#include"stdio.h"
void strcpy2(char *q[],char *p[],int n){
    int i;
    int j,m;
    for(i=0;i<n;i++)
        for(m=0;m<100&&*(p[i]+m);m++)
            *(q[i]+m)=*(p[i]+m);
    for(j=0;j<n;j++)
        printf("%s ",q[j]);
}
int main(void){
    char *p[5]={"asdg","uewnngn","sngn","fhh","mngkkd"};
    char arr[5][100] = {'\0'};
    char *q[5]={arr[0],arr[1],arr[2],arr[3],arr[4]};
    strcpy2(q,p,5);
    return 0;
}

#include <stdio.h>
void strcpy1(char q[][100], char *p[], int n)
{
    int i;
    int j, m;
    for (i = 0; i<n; i++)
        for (m = 0; m<100 && *(p[i] + m); m++)
            *(q[i] + m) = *(p[i] + m);
    for (j = 0; j<n; j++)
        printf("%s ", q[j]);
}

int main(void)
{
    char *p[5] = { "asdg", "uewnngn", "sngn", "fhh", "mngkkd" };
    char q[5][100] = { 0 };
    strcpy1(q, p, 5);

    return 0;
}