输入两个整数，第一个是行数m（不小于2，不大于23），第二个是列数（不小于2，不大于19）
按蚊香的形式旋转输出从1到m×n的整数。
如:输入3 4
     输出
     1 10 9 8
     2 11 12 7
     3 4 5 6

百度

这样问估计凉凉，我知道的。
如果是以前的我或者会敲敲，但现在不同咯~
各人有各事，最后建议翻翻类似的帖子。
搜搜蛇型矩阵。

告辞

定义四个方向
1 0   下
0 1   右
-1 0  上
0 -1  左

当前坐标 x y
下移动
x+=1 y+=0
右移动
x+=0 y+=1
注入此类

剩下的自己解决

// SpiralMatrix_2016_1.cpp : 定义控制台应用程序的入口点。
//2016年1月份螺旋矩阵! X-Bag编写

#include "stdafx.h"
#include <iostream>
#include <malloc.h>
#include <stdlib.h>
using namespace std;

int _tmain(int argc, _TCHAR* argv[])
{
    while (1)
    {
        int** array;
        int m, n;
        int step = 1;
        int point = 1;
        enum enumType { DOWN, RIGHT, UP, LEFT }MOVE = DOWN;     //定义行走方向！ 初始方向向下走！
        cout << "请输入行数：";
        cin >> m;
        cout << endl;
        cout << "请输入列数：";
        cin >> n;
        cout << endl;
        //动态分配m行n列的二维数组空间---------------------------
        array = (int**)malloc(sizeof(int*)*m);
        for (int i = 0; i < m; i++)
        {
            array[i] = (int*)malloc(sizeof(int)*n);
        }

        //动态数组赋值从1到m*n-----------------------------------
        for (int i = 0; i < m; i++)
        {
            for (int j = 0; j < n; j++)
            {
                array[i][j] = point++;
            }

        }
        //动态数组数据打印测试-----------------------------------
        for (int i = 0; i < m; i++)
        {
            for (int j = 0; j < n; j++)
            {
                cout << array[i][j] << "\t";
            }
            cout << endl;
        }


        //螺旋矩阵按步走------------------------------------------
        int   x = n, y = m;//这个是步长控制，在x方向可走n步，y方向可走m步
        int i = 0, j = 0;
        while (step <= m*n)//循环结束条件
        {
            switch (MOVE)
            {
            case DOWN:   //向下走
            {
                             for (int k = 0; k < y; k++)
                             {
                                 array[i][j] = step++;
                                 i++;
                             }
                             i--, j++;
                             MOVE = RIGHT;
                             x--;
            }
                break;
            case RIGHT:
            {
                          for (int k = 0; k < x; k++)
                          {
                              array[i][j] = step++;
                              j++;
                          }
                          j--, i--;
                          MOVE = UP;
                          y--;
            }
                break;
            case UP:
            {
                       for (int k = 0; k < y; k++)
                       {
                           array[i][j] = step++;
                           i--;
                       }
                       i++, j--;
                       MOVE = LEFT;
                       x--;
            }
                break;
            case LEFT:
            {
                         for (int k = 0; k < x; k++)
                         {
                             array[i][j] = step++;
                             j--;
                         }
                         j++, i++;
                         MOVE = DOWN;
                         y--;
            }
                break;
            default:
                break;
            }
        }

        //螺旋矩阵排序打印------------------------------------------
        cout <<m<<"行"<<n<<"列的螺旋矩阵，展示如下：\n";
        for (int i = 0; i < m; i++)
        {
            for (int j = 0; j < n; j++)
            {
                cout << array[i][j] << "\t";
            }
            cout << endl;
        }


        //释放动态开辟的二位数组空间
        for (int i = 0; i < m; i++)
        {
            free(array[i]);
        }
        free(array);
    }
    system("pause");
    return 0;
}

交作业去吧！

太稚嫩
动态分配多余

移动实现太生硬
控制变量实在太多了