Description
This is the first problem for test. Since all we know the ASCII code, your job is simple: Input numbers and output corresponding messages.
Input
The input will contain a list of positive integers separated by whitespaces(spaces, newlines, TABs). Please process to the end of file (EOF). The integers will be no less than 32.
Output
Output the corresponding message. Note there is NOT a newline character in the end of output.
Sample Input
72 101 108 108 111 44
32 119 111 114 108 100 33
Sample Output
Hello, world!

你有尝试过吗？

我想用数组，但是到第二行的时候需要换个行，不知道该怎么办了

#include <stdio.h>
int main()
{
    int ch;
    while(~scanf("%d",&ch))  {
        printf("%c",ch);
    }
    return 0;
}

换行不需要管它。

#include<stdio.h>
#include<string.h>
int main()
{   
    char a[100],b[100],i,u;      
    scanf("%d",&a[i]);   
    getchar();
    fflush(stdin);
    scanf("%d",&b[u]);
    for(i=0;i<strlen(a);i++)
        printf("%c",a[i]);
    for(u=0;u<strlen(b);u++)
        printf("%c",b[u]);
    return 0;
}
这样的话为啥结果只有个H
= =！

#include<stdio.h>
#include<string.h>
int main()
{    
    char a[100],b[100],i,u;       
    scanf("%d",&a[i]);   
    getchar();
    fflush(stdin);
    scanf("%d",&b[u]);
    for(i=0;i<strlen(a);i++)
        printf("%c",a[i]);
    for(u=0;u<strlen(b);u++)
        printf("%c",b[u]); 
    return 0;

这样的话为啥结果只有个H
= =！

没怎么懂你写的代码，
但是，清除缓冲区之后就没有读入了。