我想导入代码，但是确实无法从linux上导出，很抱歉。
这是在liunx上运行的，始终无法成功让out值按照我判断条件输出。

随后，我在codeblock上，写了简易的代码，但是结果成功运行。
有没有人能够帮我看下原因啊，非常感谢。

#include <stdio.h>
#include "string.h"
char *Kcode(char *pin,int *prd);
char *B5code(char *pdin5,int *prd);
char *B3code(char *pdin3,char *pdin5,int *prd);

char *Kcode(char *kcode,int *prd)
{
    char *out="0000000000";
    if(*prd == -1)
    {
        printf("initial kcode is %s\n",kcode);
        printf("initial *prd is %d\n",*prd);
        if(strcmp(kcode,"00011100")==0)
        {
            out ="0011110100";
            *prd = -1;
        }
        if(strcmp(kcode,"00111100")==0)
        {
            out ="0011111001";
            *prd = -1;
        }
        printf("out is %s\n",out);
        return out;
    }
}

int main()
{
    char in[100]="00011100";
    int  rd=-1;
    int  *prd=&rd;
    int  z=1;
    char din5[]="00000";
    char din3[]="000";
    char *pdin5="01010";
    char *pdin3="010";
    char *out_6b="000000";
    char *out_4b="0000";
    char *out="0000000000";
    char *ptin;
    ptin=in;

    char temp[10];
    char dout[20];

// input file
    FILE *fp1=fopen("input.txt","r");
    if(fp1 == NULL)
    {
        printf("cant find input file");
        return 0;
    }
    fgets(in,11,fp1);
    printf("input is %s\n",in);

    if(z==1){
        out=Kcode(ptin,&rd);

    }

 /*   else if(z==0){
        for(int i=0;i<3;i++)
        {
            din3[i]=in[i];
        }
        printf("din3 is %s\n",din3);
        pdin3=din3;
        printf("pdin3 is %s\n",pdin3);

        pdin5=&in[3];
        printf("pdin5 is %s\n",pdin5);

        out_6b=B5code(pdin5,&rd);
        printf("out_6b is %s\n",out_6b);
        out_4b=B3code(pdin3,pdin5,&rd);
        printf("out_4b is %s\n",out_4b);

        strcpy(dout,out_6b);
        strcpy(temp,out_4b);
        strcat(dout,temp);
        printf("final out is %s\n",dout);
    }
    else
        printf("cant recognize the code");       */
    return 0;


}