#include <stdio.h>

typedef enum {INT, SHORT, CHAR} type;

void print(const void* p_shu_zi,type t) {
    switch(t) {
    case INT:
        printf("%d\n",*(const int*)p_shu_zi);
        break;
    case SHORT:
        printf("%hd\n",*(const short*)p_shu_zi);
        break;
    case CHAR:
        printf("%c\n",*(const char*)p_shu_zi);
        break;
    }
}

int main() {
    int shu_zi = 7;
    char zi_fu = 'A';
    short duan = 17;
    printf(&shu_zi, INT);
    printf(&zi_fu, CHAR);
    printf(&duan, SHORT);
    return 0;
}

--------------------Configuration: 29whl - Win32 Debug--------------------
Compiling...
29whl.c
G:\C语言编程\WHL\29whl\29whl.c(23) : warning C4133: 'function' : incompatible types - from 'int *' to 'const char *'
G:\C语言编程\WHL\29whl\29whl.c(25) : warning C4133: 'function' : incompatible types - from 'short *' to 'const char *'

29whl.obj - 0 error(s), 2 warning(s)


打印的结果：
A烫?Press any key to continue

不兼容应该怎么解决？

将主函数中的 printf   改为 print

#include <stdio.h>

typedef enum {INT, SHORT, CHAR} type;

void print(const void* p_shu_zi,type t) {
    switch(t) {
    case INT:
        printf("%d\n",*(const int*)p_shu_zi);
        break;
    case SHORT:
        printf("%hd\n",*(const short*)p_shu_zi);
        break;
    case CHAR:
        printf("%c\n",*(const char*)p_shu_zi);
        break;
    }
}

int main() {
    int shu_zi = 7;
    char zi_fu = 'A';
    short duan = 17;
    print(&shu_zi, INT);//同楼上所说将printf改为print调用子函数
    print(&zi_fu, CHAR);
    print(&duan, SHORT);
    return 0;
}