题目要求：求所输入的上下限整数间所有整数的平方和

#include <STDIO.H>
int main()
{
    int sums,squares;
    int uper,lower;
    do
    {
    printf("enter your uper and lower:");
    scanf("%d%d",&uper,&lower);
    for(sums=0;uper>=lower;lower++)
    {
        squares=lower*lower;
        sums+=squares;
    }
    printf("%d\n",sums);
    }
    while(lower>uper);
    return 0;
}

你这样循环里面加scanf不就相当于只执行了一次循环吗？另外能不能给代码别给截图...还要打一遍很烦的

你好，为什么完善后的程序sums正确，但是uper和lower的值在输出的时候分别都增加了？
enter uper and lower integer limits:
3 1
the sums of the squares from 4 to 3 is 14.
enter uper and lower integer limits:
2 1
the sums of the squares from 3 to 2 is 5.
enter uper and lower integer limits:

lower的值会增加，uper应该是不变的，因为for循环中有lower++操作。
#include <STDIO.H>
int main(void)
 {
     int sums,squares;
     int uper,lower;
     do
     {
        printf("Enter your lower number:");
        scanf("%d",&lower);
        printf("Enter your uper number:");
        scanf("%d",&uper);
        for(sums = 0;uper >= lower;lower ++)
        {
            squares = lower*lower;
            sums += squares;
        }
        printf("The sum is %d.\n",sums);
     }
     while(lower < uper);
     return 0;
 }

#include<stdio.h>
int main(void)
{
    int min,max;
    scanf("%d%d",&min,&max);
    int k;
    if(min>max)
    {
      k=min;
      min=max;
      max=k;}
    float sum=0;
    for(int i=min;i<=max;i++)
        {int temp;
        temp=i*i;
        sum+=temp;}
        printf("%g",sum);
        return 0;
}

我觉得一个循环就可以啊

[此贴子已经被作者于2018-5-8 15:55编辑过]