写了一个squeeze(s1, s2),将字符串s1中任何与字符串s2中的字符匹配的字符全部删除
但是，打印不出来，请问是为什么
代码如下：
#include "stdafx.h"

void squeeze(char s[], char t[]) {
    int i, j, k;
    k = 0;
    for (i = 0;t[i] != '\0';i++) {
        for (j = 0;s[j] != '\0';j++) {
            if (s[j] != t[i]) {
                s[k++] = s[j];
            }
        }
    }
    s[k] = '\0';
}
int main()
{
    char s[] = "abcdefghijk";
    char t[] = "adfik";
    squeeze(s, t);
    printf("%s\n", s);
    return 0;
}

#include <stdio.h>

void squeeze(char *s, char *k, int n)
{
    for (; *s; ++s)
        k[*s] = n;
}

void _print(char *s, char *k)
{
    for (; *s; ++s)
        if (k[*s])
            printf("%c", *s);
    printf("\n");
}

int main()
{
    char s[] = "abcdefghijk";
    char t[] = "adfik";
    char k[256]={0};
    squeeze(s, k, 1);
    squeeze(t, k, 0);
    _print(s, k);
    return 0;
}

楼主程序有点问题吧，稍微改了一下
#include<stdio.h>
void squeeze(char s[], char t[])
 {
    int i, j, k;
    for (i = 0;t[i] != '\0';i++)
    {
         k = 0;
        for (j = 0;s[j] != '\0';j++)
        {
            if (s[j] != t[i])
            {
                s[k++] = s[j];
            }
        }
          s[k] = '\0';
    }
}
int main()
{
    char s[] = "abcdefghijk";
    char t[] = "adfik";
    squeeze(s, t);
    printf("%s\n", s);
    return 0;
}

谢谢你，我明白问题出在哪里了