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标题:输入年,月,日,计算是本年的第几天。两种算法,用if和函数,只用if没问题 ...
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wangtan1314
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已结贴  问题点数:20 回复次数:3 
输入年,月,日,计算是本年的第几天。两种算法,用if和函数,只用if没问题,加上函数就会出问题,求指导
#include <stdio.h>
#include <stdlib.h>
void leap();
void number();

int main()
{
    //输入年月日,求是这一年的第几天;
    int year, month,day,n;
    int sumday;
    printf("请输入年月日:");
    scanf("%d%d%d",&year,&month,&day);
    if(year % 4 == 0 && year % 100 != 0 || year % 400 == 0)
    {
        switch(month)
        {
            case 1:
                sumday = day;
                printf("今天是今年的第%d天",sumday);
                break;
            case 2:
                sumday = day + 31;
                printf("今天是今年的第%d天",sumday);
            break;
            case 3:
                sumday = day + 60;
                printf("今天是今年的第%d天",sumday);
            break;
            case 4:
                sumday = day + 91;
                printf("今天是今年的第%d天",sumday);
            break;
            case 5:
            sumday = day + 121;
                printf("今天是今年的第%d天",sumday);
            break;
            case 6:
            sumday = day + 152;
                printf("今天是今年的第%d天",sumday);
            break;
            case 7:
            sumday = day + 182;
                printf("今天是今年的第%d天",sumday);
            break;
            case 8:
            sumday = day + 213;
                printf("今天是今年的第%d天",sumday);
            break;
            case 9:
            sumday = day + 244;
                printf("今天是今年的第%d天",sumday);
            break;
            case 10:
            sumday = day + 274;
                printf("今天是今年的第%d天",sumday);
            break;
            case 11:
            sumday = day + 305;
                printf("今天是今年的第%d天",sumday);
            break;
            case 12:
            sumday = day + 335;
                printf("今天是今年的第%d天",sumday);
            break;
        }
    }
     else
    {
        switch(month)
        {
            case 1:
                sumday = day;
                printf("今天是今年的第%d天",sumday);
                break;
            case 2:
                sumday = day + 31;
                printf("今天是今年的第%d天",sumday);
            break;
            case 3:
                sumday = day + 59;
                printf("今天是今年的第%d天",sumday);
            break;
            case 4:
                sumday = day + 90;
                printf("今天是今年的第%d天",sumday);
            break;
            case 5:
            sumday = day + 120;
                printf("今天是今年的第%d天",sumday);
            break;
            case 6:
            sumday = day + 151;
                printf("今天是今年的第%d天",sumday);
            break;
            case 7:
            sumday = day + 181;
                printf("今天是今年的第%d天",sumday);
            break;
            case 8:
            sumday = day + 212;
                printf("今天是今年的第%d天",sumday);
            break;
            case 9:
            sumday = day + 243;
                printf("今天是今年的第%d天",sumday);
            break;
            case 10:
            sumday = day + 273;
                printf("今天是今年的第%d天",sumday);
            break;
            case 11:
            sumday = day + 304;
                printf("今天是今年的第%d天",sumday);
            break;
            case 12:
            sumday = day + 334;
                printf("今天是今年的第%d天",sumday);
            break;
        }
    }
    //利用函数计算
     n = number(year, month, day);
     printf("今天是今年的第%d天",sumday);
    return 0;
}
void leap(int a)
{
    if(a % 4 == 0 && a % 100 != 0 || a % 400 == 0)
        return 1;
    else
        return 0;
}
void number(int year,int month,int day)
{
    int sum = 0, i;
    int a[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
    int b[12] = {31,29,31,30,31,30,31,31,30,31,30,31};
    if(leap(year) == 1)
       for(i = 0;i < month-1; i++)
        {
            sum += b[i];
        }
    else
        for(i = 0;i < month-1; i++)
        {
            sum += a[i];
        }
    sum = sum +day;
    return sum;
}



||=== 构建: Debug 在 example14 day 中 (编译器: GNU GCC Compiler) ===|
E:\codeblocks\c class 282\example14 day\main.c||In function 'main':|
E:\codeblocks\c class 282\example14 day\main.c|13|warning: suggest parentheses around '&&' within '||' [-Wparentheses]|
E:\codeblocks\c class 282\example14 day\main.c|122|error: void value not ignored as it ought to be|
E:\codeblocks\c class 282\example14 day\main.c|9|warning: variable 'n' set but not used [-Wunused-but-set-variable]|
E:\codeblocks\c class 282\example14 day\main.c||In function 'leap':|
E:\codeblocks\c class 282\example14 day\main.c|128|warning: suggest parentheses around '&&' within '||' [-Wparentheses]|
E:\codeblocks\c class 282\example14 day\main.c|129|warning: 'return' with a value, in function returning void|
E:\codeblocks\c class 282\example14 day\main.c|131|warning: 'return' with a value, in function returning void|
E:\codeblocks\c class 282\example14 day\main.c||In function 'number':|
E:\codeblocks\c class 282\example14 day\main.c|138|error: void value not ignored as it ought to be|
E:\codeblocks\c class 282\example14 day\main.c|149|warning: 'return' with a value, in function returning void|
||=== 构建 失败: 2 error(s), 6 warning(s) (0 分, 0 秒) ===|
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2018-01-27 16:17
吹水佬
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编译方面:
//void leap();
int leap(int a);
//void number();
int number(int year,int month,int day);

//void leap(int a)
int leap(int a)

//void number(int year,int month,int day)
int number(int year,int month,int day)
2018-01-27 16:43
wangtan1314
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谢谢,已经明白,void 声明函数没有返回值,需要用int声明
2018-01-28 15:33
wangtan1314
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回复 2楼 吹水佬
谢谢大佬指教
2018-01-28 15:33
快速回复:输入年,月,日,计算是本年的第几天。两种算法,用if和函数,只用if没 ...
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