例如整形数组a[10]={0,1,1,0,1,0,1,1,0,1}   输出到文件里应该是二进制的(0110101101)占10位的内存
困扰很久了   求大神解答!

应该怎么实现呢

“占10位的内存”是什么意思？
以字节为单位来说，也要16位。
是不是这意思：


#include <stdio.h>
#include <limits.h>
#define N 10
main()
{
    char FileName[]="C:\\TEMP\\test.tmp";
    FILE *fp;
    int i, a[N]={0,1,1,0,1,0,1,1,0,1};
    unsigned short int d=0, dw;
    for (i=0; i<N; ++i)
        if (a[i]==1)
            d += 1<<(N-i-1);
    printf("BIN: ");
    for (i=0; i<N; ++i)
        printf("%d", a[i]);
    printf("\nDEC: %d\n", d);
    fp = fopen(FileName, "wb");
    fwrite(&d, sizeof(d), 1, fp);
    fclose(fp);
    fp = fopen(FileName, "rb");
    fread(&dw, sizeof(dw), 1, fp);
    fclose(fp);
    printf("BIN: ");
    for (i=sizeof(dw)*CHAR_BIT-1; i>=0; --i)
        printf("%d", (dw>>i)&1);
    printf("\nDEC: %d\n", dw);
}

[此贴子已经被作者于2017-10-26 06:11编辑过]

差不多就是这个意思   谢谢!