如何输出下列语句:
        printf("%d",a);
        scanf("%d",&a);

    printf("%s\n", "printf(\"%d\",a)");
    printf("%s\n", "scanf(\"%d\",&a)");

[此贴子已经被作者于2016-12-1 21:51编辑过]

实际代码是这样的:
#include<stdio.h>
int main(void)
{
    printf("#include <stdio.h>\n");
    printf("int main()\n");
    printf("{\n");
    printf("    int a,b;\n");
    printf("    while(scanf("%d%d",&a,&b) != EOF)");   //8
    printf("        printf("%d\n",a+b);\n");           //9
    printf("    return 0;\n");
    printf("}");

    return 0;
}
//8 error: 'd' undeclared (first use this function)
//8 error: expected')' before srring constant
//8 errpr: stray '\' in program
//9 error: expecred ')' before 'n'

#include<stdio.h>
int main(void)
{
    printf("#include <stdio.h>\n");
    printf("int main()\n");
    printf("{\n");
    printf("    int a,b;\n");
    printf("    while(scanf(\"%%d%%d\",&a,&b) != EOF)\n");
    printf("        printf(\"%%d\\n\",a+b);\n");
    printf("    return 0;\n");
    printf("}");

    return 0;
}