void judge2(int i,int j, int *win, char c1,char c2,char a)
{
    for (j = 0; j < 6; j++)
    {
        for (i = 0; i < 7; i++)
        {
            if (((a[i][j] == c1) && (a[i][j + 1] == c1) && (a[i][j + 2] == c1) && (a[i][j + 3] == c1)) || ((a[i][j] == c1) && (a[i + 1][j + 1] == c1) && (a[i + 2][j + 2] == c1) && (a[i + 3][j + 3] == c1)) || ((a[i + 1][j] == c1) && (a[i + 2][j] == c1) && (a[i + 3][j] ==c1) && (a[i][j] == c1)) || ((a[i][j] ==c1) && (a[i + 1][j - 1] == c1) && (a[i + 2][j - 2] == c1) && (a[i + 3][j - 3] == c1)))
                *win = 1;
            if (((a[i][j] == c2) && (a[i][j + 1] == c2) && (a[i][j + 2] == c2) && (a[i][j + 3] == c2)) || ((a[i][j] == c2) && (a[i + 1][j + 1] == c2) && (a[i + 2][j + 2] == c2) && (a[i + 3][j + 3] == c2)) || ((a[i + 1][j] == c2) && (a[i + 2][j] == c2) && (a[i + 3][j] == c2) && (a[i][j] == c2)) || ((a[i][j] == c2) && (a[i + 1][j - 1] == c2) && (a[i + 2][j - 2] == c2) && (a[i + 3][j - 3] == c2)))
                *win = 2;
        }
    }
}

main中的引用为:

judge2(p1, p2, &win, c[2], c[3], a[7][6]);

求解这个error显示为下标要求数组或指针类型，对象为i和j（红色为首的- -)

void judge2(int i,int j, int *win, char c1,char c2,char *a)
a使用指针

看不懂你这东东
一会 char a  一会 char * a  

哇！但是a用*后，j又不行了，所以我用的a**，可以，但是主函数中 “char”类型的实参与“char**”的形参不兼容了额

是char 额，char**是回复的