| 网站首页 | 业界新闻 | 小组 | 威客 | 人才 | 下载频道 | 博客 | 代码贴 | 在线编程 | 编程论坛
欢迎加入我们,一同切磋技术
用户名:   
 
密 码:  
共有 1193 人关注过本帖
标题:C语言求解欧拉方程组
只看楼主 加入收藏
shizy
Rank: 1
等 级:新手上路
帖 子:1
专家分:0
注 册:2016-8-8
收藏
 问题点数:0 回复次数:0 
C语言求解欧拉方程组
以下是我的需要写代码的公式
图片附件: 游客没有浏览图片的权限,请 登录注册

一下是代码
程序代码:
//改进的Lax-Wendroff的MacCormack格式.cpp
//利用差分格式求解二维欧拉方程问题
//date 20160725-0801
#include <stdio.h>
#include <stdlib.h>
#include <math.h>
#define GAMA 1.4//气体常数
#define MIN(x,y) (((x)<(y))?(x):(y))
#define L 0.05//涡核尺寸
#define Lx (20.0*L)//计算区域
#define Ly (20.0*L)
#define Tmax 3//总时间
#define Sf 0.8//时间步长因子
#define nx 40//网格数
#define ny 40

//全局变量
double rho[nx+2][ny+2],    ux[nx+2][ny+2],    uy[nx+2][ny+2], e[nx+2][ny+2];//rho(i,j,t)
double par_rho[nx+2][ny+2],    par_ux[nx+2][ny+2],    par_uy[nx+2][ny+2],par_e[nx+2][ny+2],par_p[nx+2][ny+2];//partial_rho(i,j,t)
double rho_ave[nx+2][ny+2],    ux_ave[nx+2][ny+2],    uy_ave[nx+2][ny+2], e_ave[nx+2][ny+2],p_ave[nx+2][ny+2];//rho_ave(i,j,t+dt)
double par_rho_ave[nx+2][ny+2],    par_ux_ave[nx+2][ny+2],par_uy_ave[nx+2][ny+2], par_e_ave[nx+2][ny+2];//partial_rho_ave(i,j,t+dt)
double rho_t[nx+2][ny+2],ux_t[nx+2][ny+2],uy_t[nx+2][ny+2], e_t[nx+2][ny+2];//rho(i,j,t+dt)
double dx=Lx/nx,dy=Ly/ny;

//函数声明
void    Initial(double rho[nx+2][ny+2],double ux[nx+2][ny+2],double uy[nx+2][ny+2],double  e[nx+2][ny+2]);
double  Cal_time_step(double rho[nx+2][ny+2],double    ux[nx+2][ny+2],double uy[nx+2][ny+2],double e[nx+2][ny+2]);
void    Mac_Cormack_2DSolver(double rho[nx+2][ny+2],double ux[nx+2][ny+2],double uy[nx+2][ny+2],double e[nx+2][ny+2],double dt);
void    boundary(double rho_t[nx+2][ny+2],double ux_t[nx+2][ny+2],double uy_t[nx+2][ny+2],double e_t[nx+2][ny+2]);
void    output(double rho[nx+2][ny+2],double ux[nx+2][ny+2],double uy[nx+2][ny+2],double e[nx+2][ny+2]);

//主函数
void main()
{
    double t,dt;
    double rho1,u1,v1,p1;
    int i,j,w=0;
    Initial(rho, ux, uy, e); //初始化
               FILE *fp1;
                fp1=fopen("initial_result.txt","w");
                for(i=0;i<=nx+1;i++)
                    for(j=0;j<=ny+1;j++)
                      {
                       rho1=rho[i][j];
                       u1=ux[i][j];
                       v1=uy[i][j];
                       p1=(GAMA-1)*(e[i][j]-0.5*rho1*(u1*u1+v1*v1));
                       fprintf(fp1,"%e %e %e %e %e %e  %e \n",i*dx,j*dy,rho1,u1,v1,p1,e[i][j]);
                      }
                fclose(fp1);
    t=0;
    while(t<Tmax)
         {
          //dt=0.01;
          dt=Cal_time_step(rho,ux, uy, e);//计算时间步长dt
          t+=dt;
          printf("t=%10g ,dt=%10g\n",t,dt);

         Mac_Cormack_2DSolver( rho, ux,uy,e,dt);//二维差分格式
        //exit(0);
        w++;
         }
    output(rho,ux,uy, e);//数据保存
}





/*-----------------------------------------------------------------
初始化;
--------------------------------------------------------------------*/
void Initial(double rho[nx+2][ny+2],double ux[nx+2][ny+2],double uy[nx+2][ny+2],double e[nx+2][ny+2] )//初始化
{

 int i,j;

 double pinf=1.0, rouinf=1.0,    epsllion=0.3,    alpha=0.204;//初始条件
 double x0=Lx/2.0, y0=Ly/2.0, r0, tau,theta,eps=0.0;

 for(j=0;j<=ny+1;j++)
  for(i=0;i<=nx+1;i++)
  {
    theta=atan((j*dy-y0)/(i*dx-x0));
    r0=sqrt((i*dx-x0)*(i*dx-x0)+(j*dy-y0)*(j*dy-y0));
    tau=r0/L;
    rho[i][j]=rouinf*(pow((1-(GAMA-1)/(4*alpha*GAMA)*epsllion*epsllion*(exp(2*alpha*(1-tau*tau)))),(1/(GAMA-1)))-1)+eps;
     ux[i][j]= epsllion*tau*exp(alpha*(1-tau*tau))*sin(theta)+eps;
     uy[i][j]=-epsllion*tau*exp(alpha*(1-tau*tau))*cos(theta)+eps;
      e[i][j]=rho[i][j]/(GAMA-1)+1/2*rho[i][j]*(ux[i][j]*ux[i][j]+uy[i][j]*uy[i][j])+eps;
    //printf("%e\t%e\t%e\t%e\t%e\t%e\t%e\n\n",theta,r0,tau,rho[i][j],ux[i][j],uy[i][j],e[i][j]);
  }
  printf("初始化已完成\n\n");
}



/*--------------------------------------------------------------------
计算时间步长返回: 时间步长。
--------------------------------------------------------------------*/
double Cal_time_step(double rho[nx+2][ny+2],double ux[nx+2][ny+2],double uy[nx+2][ny+2],double e[nx+2][ny+2])
{

 int i,j;

 double maxvel,p0,u0,v0,vel,rho0,e0;

 maxvel=1e-50;

 for(i=1;i<=nx;i++)
  for(j=1;j<=ny;j++)
  {
   //printf("rho=%e  %e  %e  %e\n",rho[i][j],ux[i][j],uy[i][j],e[i][j]);
   rho0=rho[i][j];
   u0=ux[i][j];
   v0=uy[i][j];
   e0=e[i][j];
   p0=(GAMA-1)*(e0-0.5*rho0*(u0*u0+v0*v0));
   vel=sqrt(fabs(GAMA*p0/rho0))+sqrt(u0*u0+v0*v0);                //CFL准则
  // printf("%e  %e\n",p0,vel);
   if(vel>maxvel)    maxvel=vel;
   //printf("%e\t%e\t%e\t%e\t%e\n",rho0,u0,v0,p0,vel);
  }

 return Sf*MIN(dx,dy)/maxvel;
}


/*--------------------------------------------------------------------
差分格式
--------------------------------------------------------------------*/
void  Mac_Cormack_2DSolver(double rho[nx+2][ny+2],double ux[nx+2][ny+2],double uy[nx+2][ny+2],double e[nx+2][ny+2],double dt)
{
    int  i,j;
    double A1,A2,A3,A4,B1,B2,B3,C1,C2,C3,D1,D2,D3,D4,pi0j0,pi0j1,pi1j0,pi1j1;
//预测值
    for(i=1;i<nx+1;i++)
        {
            for(j=1;j<ny+1;j++)
             {
                //printf("rho=%e  %e  %e  %e\n",rho[i][j],ux[i][j],uy[i][j],e[i][j]);}}
                pi0j0=(GAMA-1)*(e[i][j]-0.5*rho[i][j]*ux[i][j]*ux[i][j]);
                pi0j1=(GAMA-1)*(e[i][j+1]-0.5*rho[i][j+1]*ux[i][j+1]*ux[i][j+1]);
                pi1j0=(GAMA-1)*(e[i+1][j]-0.5*rho[i+1][j]*ux[i+1][j]*ux[i+1][j]);
                pi1j1=(GAMA-1)*(e[i+1][j+1]-0.5*rho[i+1][j+1]*ux[i+1][j+1]*ux[i+1][j+1]);

                A1=rho[i][j]*(ux[i+1][j]-ux[i][j])/dx;
                A2=ux[i][j]*(rho[i+1][j]-rho[i][j])/dx;
                A3=rho[i][j]*(uy[i][j+1]-uy[i][j])/dy;
                A4=uy[i][j]*(rho[i][j+1]-rho[i][j])/dy;
                par_rho[i][j]=-(A1+A2+A3+A4);

                B1=ux[i][j]*(ux[i+1][j]-ux[i][j])/dx;
                B2=uy[i][j]*(ux[i][j+1]-ux[i][j])/dy;
                B3=1.0/rho[i][j]*(pi1j0-pi0j0)/dx;
                par_ux[i][j]=-(B1+B2+B3);

                C1=ux[i][j]*(uy[i+1][j]-uy[i][j])/dx;
                C2=uy[i][j]*(uy[i][j+1]-uy[i][j])/dy;
                C3=1.0/rho[i][j]*(pi0j1-pi0j0)/dy;
                par_uy[i][j]=-(C1+C2+C3);

                D1=ux[i][j]*(e[i+1][j]-e[i][j])/dx;
                D2=uy[i][j]*(e[i][j+1]-e[i][j])/dy;
                D3=pi0j0/rho[i][j]*(ux[i+1][j]-ux[i][j])/dx;
                D4=pi0j0/rho[i][j]*(uy[i][j+1]-uy[i][j])/dy;
                par_e[i][j]=-(D1+D2+D3+D4);
        //printf("par_rho=%e,ux=%e,uy=%e,e=%e\n",par_rho[i][j],par_ux[i][j],par_uy[i][j],par_e[i][j]);

             }
        }

/*校正值,暂时未考虑人工黏滞项*/
    for(i=1;i<nx+1;i++)
        for(j=1;j<ny+1;j++)
        {
            rho_ave[i][j]=rho[i][j]+par_rho[i][j]*dt;//粘滞性加在这里
             ux_ave[i][j]= ux[i][j]+ par_ux[i][j]*dt;//粘滞性加在这里
             uy_ave[i][j]= uy[i][j]+ par_uy[i][j]*dt;//粘滞性加在这里
              e_ave[i][j]=  e[i][j]+  par_e[i][j]*dt;//粘滞性加在这里
              p_ave[i][j]=(GAMA-1)*(e_ave[i][j]-0.5*rho_ave[i][j]*ux_ave[i][j]*ux_ave[i][j]);

        }
        double F1,F2,F3,F4,G1,G2,G3,H1,H2,H3,J1,J2,J3,J4;
        for(i=1;i<nx+1;i++)
            for(j=1;j<ny+1;j++)
        {
            F1=rho_ave[i][j]*(ux_ave[i][j]-ux_ave[i-1][j])/dx;
            F2=ux_ave[i][j]*(rho_ave[i][j]-rho_ave[i-1][j])/dx;
            F3=rho_ave[i][j]*(uy_ave[i][j]-uy_ave[i][j-1])/dy;
            F4=uy_ave[i][j]*(rho_ave[i][j]-rho_ave[i][j-1])/dy;
            par_rho_ave[i][j]=-(F1+F2+F3+F4);

            G1=ux_ave[i][j]*(ux_ave[i][j]-ux_ave[i-1][j])/dx;
            G2=uy_ave[i][j]*(ux_ave[i][j]-ux_ave[i][j-1])/dy;
            G3=1.0/rho_ave[i][j]*(p_ave[i][j]-p_ave[i-1][j])/dx;
            par_ux_ave[i][j]=-(G1+G2+G3);

            H1=ux_ave[i][j]*(uy_ave[i][j]-uy_ave[i-1][j])/dx;
            H2=uy_ave[i][j]*(uy_ave[i][j]-uy_ave[i][j-1])/dy;
            H3=1.0/rho_ave[i][j]*(p_ave[i][j]-p_ave[i][j-1])/dy;
            par_uy_ave[i][j]=-(H1+H2+H3);

            J1=ux_ave[i][j]*(e_ave[i][j]-e_ave[i-1][j])/dx;
            J2=uy_ave[i][j]*(e_ave[i][j]-e_ave[i][j-1])/dy;
            J3=p_ave[i][j]/rho_ave[i][j]*(ux_ave[i][j]-ux_ave[i-1][j])/dx;
            J4=p_ave[i][j]/rho_ave[i][j]*(uy_ave[i][j]-uy_ave[i][j-1])/dy;
            par_e_ave[i][j]=-(J1+J2+J3+J4);
        }
//预测加校正
        for(i=1;i<nx+1;i++)
            for(j=1;j<ny+1;j++)
            {
                rho_t[i][j]=rho[i][j]+0.5*(par_rho[i][j]+par_rho_ave[i][j]);
                 ux_t[i][j]= ux[i][j]+0.5*( par_ux[i][j]+ par_ux_ave[i][j]);
                 uy_t[i][j]= uy[i][j]+0.5*( par_uy[i][j]+ par_uy_ave[i][j]);
                  e_t[i][j]=  e[i][j]+0.5*(  par_e[i][j]+  par_e_ave[i][j]);
            }


//加入边界条件
 boundary( rho_t, ux_t, uy_t, e_t);


//把t+dt时刻值赋给t,做为下一时刻的起始值
        for(i=0;i<=nx+1;i++)
            for(j=0;j<=ny+1;j++)
            {
                rho[i][j]=rho_t[i][j];
                 ux[i][j]= ux_t[i][j];
                 uy[i][j]= uy_t[i][j];
                  e[i][j]= e_t[i][j];
            }

}


/*--------------------------------------------------------------------
边界条件
--------------------------------------------------------------------*/
void boundary(double rho_t[nx+2][ny+2],double ux_t[nx+2][ny+2],double uy_t[nx+2][ny+2],double e_t[nx+2][ny+2])
{
    int i,j;
    //左边界
    for(j=0;j<=nx+1;j++)
    {
        i=0;
        rho_t[i][j]=2.0*rho_t[1][j]-rho_t[2][j];
         ux_t[i][j]= 2.0*ux_t[1][j]- ux_t[2][j];
         uy_t[i][j]= 2.0*uy_t[1][j]- uy_t[2][j];
          e_t[i][j]=  2.0*e_t[1][j]-  e_t[2][j];
    }
    //右边界
    for(j=0;j<=nx+1;j++)
    {
        i=nx+1;
        rho_t[i][j]=2.0*rho_t[nx][j]-rho_t[nx-1][j];
         ux_t[i][j]= 2.0*ux_t[nx][j]- ux_t[nx-1][j];
         uy_t[i][j]= 2.0*uy_t[nx][j]- uy_t[nx-1][j];
          e_t[i][j]=  2.0*e_t[nx][j]-  e_t[nx-1][j];
    }
    //下边界
for(i=0;i<=ny+1;i++)
    {
        j=0;
        rho_t[i][j]=2.0*rho_t[i][1]-rho_t[i][2];
         ux_t[i][j]= 2.0*ux_t[i][1]- ux_t[i][2];
         uy_t[i][j]= 2.0*uy_t[i][1]- uy_t[i][2];
          e_t[i][j]=  2.0*e_t[i][1]-  e_t[i][2];
    }
    //上边界
for(i=0;i<=ny+1;i++)
    {
        j=ny+1;
        rho_t[i][j]=2.0*rho_t[i][ny]-rho_t[i][ny-1];
         ux_t[i][j]= 2.0*ux_t[i][ny]- ux_t[i][ny-1];
         uy_t[i][j]= 2.0*uy_t[i][ny]- uy_t[i][ny-1];
          e_t[i][j]=  2.0*e_t[i][ny]-  e_t[i][ny-1];
    }
}


/*-------------------------------------------------------
输出文件格式数据
---------------------------------------------------------*/
void output(double rho[nx+2][ny+2],double ux[nx+2][ny+2],double uy[nx+2][ny+2],double e[nx+2][ny+2])
{
     int i,j;
     FILE *fp;
     double rho1,u1,v1,p1;
     fp=fopen("result0.txt","w");
     for(i=0;i<=nx+1;i++)
      for(j=0;j<=ny+1;j++)
          {
           rho1=rho[i][j];
           u1=ux[i][j];
           v1=uy[i][j];
           p1=(GAMA-1)*(e[i][j]-0.5*rho1*(u1*u1+v1*v1));
           fprintf(fp,"%20f %20f %20.10e %20.10e %20.10e %20.10e  %20.10e \n",i*dx,j*dy,rho1,u1,v1,p1,e[i][j]);
          }
    fclose(fp);
}

不知道那里有误?帮忙看一下,可以运行结果不对。
搜索更多相关主题的帖子: include 方程组 C语言 
2016-08-08 15:30
快速回复:C语言求解欧拉方程组
数据加载中...
 
   



关于我们 | 广告合作 | 编程中国 | 清除Cookies | TOP | 手机版

编程中国 版权所有,并保留所有权利。
Powered by Discuz, Processed in 0.035722 second(s), 9 queries.
Copyright©2004-2024, BCCN.NET, All Rights Reserved