这个程序在get nights()模块输入非整数,程序还是会继续运行,请问是什么问题?
#include <stdio.h>#define QUIT 5
#define HOTEL1 80.00
#define HOTEL2 125.00
#define HOTEL3 155.00
#define HOTEL4 200.00
#define DISCOUNT 0.95
#define STARS "***************************"
int menu();
int getnights();
void showprice(double, int);
int main()
{
int nights;
double hotel_rate;
int code;
while((code = menu()) != QUIT)
{
switch(code)
{
case 1: hotel_rate = HOTEL1;
break;
case 2: hotel_rate = HOTEL2;
break;
case 3: hotel_rate = HOTEL3;
break;
case 4: hotel_rate = HOTEL4;
break;
default: hotel_rate = 0.0;
printf("Oops!\n");
break;
}
nights = getnights();
showprice(hotel_rate, nights);
}
printf("Thank you and goodbye. ");
return 0;
}
int menu()
{
int code, status;
printf("\n%s%s\n", STARS, STARS);
printf("Enter the number of the desired hotel: \n");
printf("1) Fairfield Arms 2) Hotel Olympic\n");
printf("3) Chertworthy Plaza 4) The Stockton\n");
printf("5) quit\n");
printf("%s%s\n", STARS, STARS);
while((status = scanf("%d", &code)) != 1 ||
(code < 1 || code > 5))
{
if(status != 1)
scanf("%*s");
printf("Enter an integer from 1 to 5, please.\n");
}
return code;
}
int getnights()
{
int nights;
printf("How mant nights are needed? ");
while(scanf("%d", &nights) != 1)
{
scanf("%*s");
printf("Please enter an integer, such as 2.\n");
}
return nights;
}
void showprice(double rate, int nights)
{
int n;
double total = 0.0;
double factor = 1.0;
for(n = 1; n <= nights; n++, factor *= DISCOUNT)
total += rate * factor;
printf("The total cost will be $%0.2f. \n", total);
}
输入4.1 结果是
4.1
How mant nights are needed? Please enter an integer, such as 2.
因为这个模块上的while语句里已经限定了输入值必须是整数才会输出how many nights are needed?但不知怎么的输入浮点数之后循环和外部同时进行,百思不得其解。求教