#include<stdio.h>
#define N 20
void matrx1(int a[][N],int m,int n)
{
    int d,x=0,y=0;
    int right,left,up,down;
    for(d=1;d<=m*n;d++)
    {
        a[x][y]=d;
        right=y<n-1&&a[x][y+1]==0;
        left=y>0&&a[x][y-1]==0;
        down=x<m-1&&a[x+1][y]==0;
        up=x>0&&a[x-1][y]==0;
    /*    if(right||down)
            y++;
        else
            x++;
        if(down||left)
            x++;
        else if(left||up)
            y--;
        else if(up||right)
            x--;*/
     if(right)
        {
            if(up)
                x--;
            else
                y++;
        }
     else  if(left)
        {
        if(down)
            x++;
            else
                y--;
        }
     else if(down)
        {
            if(right)
                y++;
            else
                x++;
        }

    else if(up)
        {
            if(left)
                    y--;
            else
                    x--;
        }

}

}
void output(int a[][N],int m, int n)
{
    int i,j;
    for(i=0;i<m;i++)
    {
        for(j=0;j<n;j++)
            printf("%4d",a[i][j]);
          printf("\n");
    }

}
void main()
{
    int a[N][N]={0};
    int m,n;
    printf("please input num:\n");
    scanf("%d%d",&m,&n);
    matrx1(a,m,n);
    output(a,m,n);
}

明天要答辩

很急

在线等

#include<stdio.h>
 #define N 20
 void matrx1(int a[][N],int m,int n)
 {
     int d,x=0,y=0;
     int right,left,up,down;
     for(d=1;d<=m*n;d++)
     {
         a[x][y]=d;
         right=y<n-1&&a[x][y+1]==0;     //向右赋值的条件   满足会赋1不满足赋0给right
         left=y>0&&a[x][y-1]==0;        //向左赋值的条件   满足会赋1不满足赋0给left
         down=x<m-1&&a[x+1][y]==0;      //向下赋值的条件   满足会赋1不满足赋0给down
         up=x>0&&a[x-1][y]==0;          //向上赋值的条件   满足会赋1不满足赋0给up
     /*    if(right||down)
             y++;
         else
             x++;
         if(down||left)
             x++;
         else if(left||up)
             y--;
         else if(up||right)
             x--;*/
      if(right)
         {
             if(up)
                 x--;
             else
                 y++;
         }
      else  if(left)
         {
         if(down)
             x++;
             else
                 y--;
         }
      else if(down)
         {
             if(right)
                 y++;
             else
                 x++;
         }

     else if(up)
         {
             if(left)
                     y--;
             else
                     x--;
         }

 }

 }
void output(int a[][N],int m, int n)    //按从上到下 从左到右输出数组到显示器
 {
     int i,j;
     for(i=0;i<m;i++)
     {
         for(j=0;j<n;j++)
             printf("%4d",a[i][j]);
           printf("\n");
     }

 }
 void main()
 {
     int a[N][N]={0};
     int m,n;
     printf("please input num:\n");
     scanf("%d%d",&m,&n);
     matrx1(a,m,n);
     output(a,m,n);
 }

收到的鲜花

• a2421524188 于 2016-06-28 00:08 送鲜花  3朵   附言：我很赞同

m行n列二维整型数组中：
满足向右赋值的条件为 右边的数为零且未到第n列
满足向左赋值的条件为 左边的数为零且未到第一列
满足向下赋值的条件为 下边的数为零且未到第m行
满足向上赋值的条件为  上边的数为零且未到第一行

您好！可以帮我用vb做一个程序吗？门禁程序要有四次刷卡记录，谢谢  我的邮箱918969924@

此程序利用else与if语句，bi jiao 2 shu zhi jian zui da zhe

前几行能都给个注释吗

前几个很好理解啊

收到的鲜花

• a2421524188 于 2016-06-28 00:07 送鲜花  3朵   附言：我很赞同