#include<stdio.h>
int main()
{
    int n,m,s[60][6],i,j,k;
    double x[60],y[6],sum;
    while((scanf("%d %d",&n,&m)!=EOF)&&n&&m)
    {
        for(i=0;i<n;i++)
            for(j=0;j<m;j++)
                scanf("%d",&s[i][j]);
        for(i=0;i<n;i++)
        {
            sum=0;
            for(j=0;j<m;j++)
            {
                sum+=s[i][j];
            }
            x[i]=sum*(1.0)/m;
        }
        for(i=0;i<n;i++)
        {
            if(i==n-1)
                printf("%.2lf\n",x[i]);
            else
                printf("%.2lf ",x[i]);
        }
//************************
//************************
        for(j=0;j<m;j++)
        {
            sum=0;
            for(i=0;i<n;i++)
            {
                sum+=s[i][j];
            }
            y[j]=sum*(1.0)/n;
        }
        for(j=0;j<m;j++)
        {
            if(j==m-1)
                printf("%.2lf\n",y[j]);
            else
                printf("%.2lf ",y[j]);
        }
//***************************
        for(i=0;i<n;i++)
        {
            k=0;
            for(j=0;j<m;j++)
            {
                if(x[i]<s[i][j])
                    k++;
            }
        }
        printf("%d\n",k);
    }
    return 0;
}#include<stdio.h>
int main()
{
    int n,m,s[60][6],i,j,k;
    double x[60],y[6],sum;
    while((scanf("%d %d",&n,&m)!=EOF)&&n&&m)
    {
        for(i=0;i<n;i++)
            for(j=0;j<m;j++)
                scanf("%d",&s[i][j]);
        for(i=0;i<n;i++)
        {
            sum=0;
            for(j=0;j<m;j++)
            {
                sum+=s[i][j];
            }
            x[i]=sum*(1.0)/m;
        }
        for(i=0;i<n;i++)
        {
            if(i==n-1)
                printf("%.2lf\n",x[i]);
            else
                printf("%.2lf ",x[i]);
        }
//************************
//************************
        for(j=0;j<m;j++)
        {
            sum=0;
            for(i=0;i<n;i++)
            {
                sum+=s[i][j];
            }
            y[j]=sum*(1.0)/n;
        }
        for(j=0;j<m;j++)
        {
            if(j==m-1)
                printf("%.2lf\n",y[j]);
            else
                printf("%.2lf ",y[j]);
        }
//***************************
        for(i=0;i<n;i++)
        {
            k=0;
            for(j=0;j<m;j++)
            {
                if(x[i]<s[i][j])
                    k++;
            }
        }
        printf("%d\n",k);
    }
    return 0;
}

简单说说这段代码是处理什么问题的？

搜索了老半天，终于知道要解决什么问题了 http://acm.hdu.
楼主真有意思，既要别人解决问题，却又不肯告诉别人问题是什么；或者楼主就是希望看到每一个人都去网上浪费大量时间搜索题目。