C#实现MYSQL数据库保存和读取图片,大神,求助
读取图片时 Image image = Image.FromStream(MStream);参数无效,求大神帮助。具体程序如下:using System;
using System.Collections.Generic;
using
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;
using MySql.Data.MySqlClient;
using
namespace ByteImage
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
#region 定义公共的类对象及变量
MySqlConnection sqlcon; //声明数据库连接对象
MySqlDataAdapter sqlda; //声明数据桥接器对象
DataSet myds; //声明数据集对象
//定义数据库连接字符串
#endregion
private void Form1_Load(object sender, EventArgs e)
{
ShowInfo(); //显示图片信息
}
private void button1_Click(object sender, EventArgs e)
{
//定义可选择的图片类型
openFileDialog1.Filter = "*.jpg,*jpeg,*.bmp,*.ico,*.png,*.tif,*.wmf|*.jpg;*jpeg;*.bmp;*.ico;*.png;*.tif;*.wmf";
openFileDialog1.Title = "选择图片";
//判断是否选择了图片
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
//显示选择的图片
pictureBox1.Image = Image.FromFile(openFileDialog1.FileName);
}
}
private void button2_Click(object sender, EventArgs e)
{
if (openFileDialog1.FileName != "" && textBox1.Text != "")
{
//添加图片信息
if (AddInfo(textBox1.Text, openFileDialog1.FileName))
{
MessageBox.Show("图片信息添加成功");
}
}
ShowInfo();
}
private void dataGridView1_CellContentClick(object sender, DataGridViewCellEventArgs e)
{ //记录选择的用户名
string strName = dataGridView1.Rows[e.RowIndex].Cells[0].Value.ToString();
if (strName != "")
{ //数据桥接器对象
MySqlConnection sqlco = new MySqlConnection("Server=localhost;Uid=root;Password=123456;Database=test");
sqlda = new MySqlDataAdapter("select * from tb_image where name='" + strName + "'", sqlco);
myds = new DataSet(); //数据集对象
sqlda.Fill(myds); //填充数据集
//显示图片名称
textBox1.Text = myds.Tables[0].Rows[0][0].ToString();
//使用数据库中存储的二进制图片实例化内存数据流
MemoryStream MStream = new MemoryStream((byte[])myds.Tables[0].Rows[0]["photo"]);
Image image = Image.FromStream(MStream); 此处出错,显示参数无效
pictureBox1.Image = image; //显示图片
}
}
#region 添加图片信息
private bool AddInfo(string strName, string strImage)
{
sqlcon = new MySqlConnection(); //strCon
FileStream FStream = new FileStream(strImage, FileMode.Open, FileAccess.Read);
BinaryReader BReader = new BinaryReader(FStream);
byte[] byteImage = BReader.ReadBytes((int)FStream.Length);
MySqlConnection conn = new MySqlConnection("Server=localhost;Uid=root;Password=123456;Database=test");
conn.Open();
MySqlCommand comm = new MySqlCommand("insert into tb_image(name,photo) values(?name,?photo)", sqlcon);
comm.Connection = conn;
comm.Parameters.Add("?name",MySqlDbType.VarChar).Value=strName;
comm.Parameters.Add("?photo",MySqlDbType.VarChar).Value = strImage;
comm.ExecuteNonQuery();
conn.Close();
return true;
}
#endregion
#region 在DataGridView中显示图片名称
private void ShowInfo()
{
MySqlConnection sqlcon = new MySqlConnection("Server=localhost;Uid=root;Password=123456;Database=test");
sqlda = new MySqlDataAdapter("select name as name from tb_image", sqlcon);
myds = new DataSet();
sqlda.Fill(myds);
dataGridView1.DataSource = myds.Tables[0];
}
#endregion
}
}