从键盘获取一个short整数，计算它有多少个bit是1.
#include <stdio.h>
#include<stdlib.h>
#include<tchar.h>
#include<conio.h>
#include<string.h>

int main(void)
{
    printf("请随意按键：");
    short int n;
    scanf_s("%d", &n);
    int q = 0;
    int num = 1;
    int f = n;
    while (q < 16)
    {
        
        if (((f = f >> q) & 1) == 1)
        {
            num = num + 1;
        }
        q++;

    }
    printf("该整数有%d个bit是1", num);
    system("pause");
    return 0;

}
我写的但是超过15就不对了。而且每次都报错Run-Time Check Failure #2 - Stack around the variable 'n' was corrupted.

[此贴子已经被作者于2016-5-23 22:39编辑过]

#include <stdio.h>

main()
{
    printf("请随意按键：");
    short int n;
    scanf("%hd", &n);
    printf("DEC: %hd\n", n);
    printf("BIN: ");
    int num=0;
    for (int b=0, i=0; i<16; i++)
    {
        b = (n>>(15-i))&1;
        num += (b != 0) ? 1 : 0;
        printf("%d", b);
    }
    printf("\n该整数有%d个bit是1", num);
}

[此贴子已经被作者于2016-5-24 00:18编辑过]