/*有n个整数，使前面各数顺序 向后移动m个位置，最后m个数变成最前面m个数，写一函数实现以止功能，在主函数中输入n个整数和输出调整后的n个数
*/
#include<stdio.h>
int main ()
{
    void move(int [20],int,int);
    int number[20],n,m,i;
    printf("How many numbers :");  
    scanf_s("%d",&n);
    printf("input %d numbers",n);
    for(i=0;i<n;i++)
        scanf_s("%d",&number[i]);
    printf("how many do you want to move:");
        scanf_s("%d",&m);
    move(number,n,m);
    printf("Now they are :\n");
    for(i=0;i<n;i++)
        printf("  %d  ",&number[i]);
    return 0;

}

void move(int aray[20],int n,int m)
{
    int * p,aray_end;
    aray_end=*(aray+n-1);
    for(p=aray+n-1;p>aray;p--)
        *p=*(p-1);
    *aray=aray_end;
    m--;
    if(m>0)
        move(aray,n,m);
}

/*
输出为:
How many numbers :8
input 8 numbers 12 43 65 67 8 2 7 11
how many do you want to move:4
Now they are :
  3406224    3406228    3406232    3406236    3406240    3406244    3406248    3406252  请按任意键继续. .
???不知道哪错了最后我想要的是：
Now they are :
8 2 7 11 12 43 65 67
*/

#include<stdio.h>
int main ()
{
    void move(int [20],int,int);
    int number[20],n,m,i;
    printf("How many numbers :");  
    scanf_s("%d",&n);
    printf("input %d numbers",n);
    for(i=0;i<n;i++)
        scanf_s("%d",&number[i]);
    printf("how many do you want to move:");
        scanf_s("%d",&m);
    move(number,n,m);
    printf("Now they are :\n");
    for(i=0;i<n;i++)
        printf("  %d  ",number[i]);
    return 0;

}

void move(int aray[20],int n,int m)
{
    int * p,aray_end;
    aray_end=*(aray+n-1);
    for(p=aray+n-1;p>aray;p--)
        *p=*(p-1);
    *aray=aray_end;
    m--;
    if(m>0)
        move(aray,n,m);
}

谢谢你

不客气，写的不错。。。