【求助】黄金分割求极值，编译通不过，求教！
我将某统计语言的黄金分割求最小值的函数复制过来，然后试试，居然无法编译通过，请高手指教！代码：
#include <stdlib.h>
#include <float.h>
#include <stdio.h>
#include <math.h>
double minfun(double x)
{
return(sin(x) + cos(x));
}
double fmin(double ax, double bx, double f(double, void *), void *info, double tol)
{
/* c is the squared inverse of the golden ratio */
const double c = (3. - sqrt(5.)) * .5;
/* Local variables */
double a, b, d, e, p, q, r, u, v, w, x;
double t2, fu, fv, fw, fx, xm, eps, tol1, tol3;
/* eps is approximately the square root of the relative machine precision. */
eps = DBL_EPSILON;
tol1 = eps + 1.;/* the smallest 1.000... > 1 */
eps = sqrt(eps);
a = ax;
b = bx;
v = a + c * (b - a);
w = v;
x = v;
d = 0.;/* -Wall */
e = 0.;
fx = (*f)(x, info);
fv = fx;
fw = fx;
tol3 = tol / 3.;
/* main loop starts here ----------------------------------- */
for(;;) {
xm = (a + b) * .5;
tol1 = eps * fabs(x) + tol3;
t2 = tol1 * 2.;
/* check stopping criterion */
if (fabs(x - xm) <= t2 - (b - a) * .5) break;
p = 0.;
q = 0.;
r = 0.;
if (fabs(e) > tol1) { /* fit parabola */
r = (x - w) * (fx - fv);
q = (x - v) * (fx - fw);
p = (x - v) * q - (x - w) * r;
q = (q - r) * 2.;
if (q > 0.) p = -p; else q = -q;
r = e;
e = d;
}
if (fabs(p) >= fabs(q * .5 * r) ||
p <= q * (a - x) || p >= q * (b - x)) { /* a golden-section step */
if (x < xm) e = b - x; else e = a - x;
d = c * e;
}
else { /* a parabolic-interpolation step */
d = p / q;
u = x + d;
/* f must not be evaluated too close to ax or bx */
if (u - a < t2 || b - u < t2) {
d = tol1;
if (x >= xm) d = -d;
}
}
/* f must not be evaluated too close to x */
if (fabs(d) >= tol1)
u = x + d;
else if (d > 0.)
u = x + tol1;
else
u = x - tol1;
fu = (*f)(u, info);
/* update a, b, v, w, and x */
if (fu <= fx) {
if (u < x) b = x; else a = x;
v = w; w = x; x = u;
fv = fw; fw = fx; fx = fu;
} else {
if (u < x) a = u; else b = u;
if (fu <= fw || w == x) {
v = w; fv = fw;
w = u; fw = fu;
} else if (fu <= fv || v == x || v == w) {
v = u; fv = fu;
}
}
}
/* end of main loop */
return x;
}
void main()
{
double minfun();
eps = 1e-10;
fx = fmin(0.0, 2.0,minfun,eps);
printf("%f\n", fx);
return;
}
用gcc编译出现的错误如下：
test.c:14:8: error: conflicting types for 'fmin'
test.c: In function 'main':
test.c:120:2: error: 'eps' undeclared (first use in this function)
test.c:120:2: note: each undeclared identifier is reported only once for each function it appears in
test.c:121:2: error: 'fx' undeclared (first use in this function)
test.c:121:2: warning: passing argument 3 of 'fmin' from incompatible pointer type [enabled by default]
test.c:14:8: note: expected 'double (*)(double, void *)' but argument is of type 'double (*)(double)'
test.c:121:2: error: too few arguments to function 'fmin'
test.c:14:8: note: declared here
第一次使用函数作为另一个函数的变量，不怎么懂，敬请指教！
