大家好，我在学习c语言，遇到一个问题不知道哪里出了毛病！请看内容！
c语言教科书里面第三章有道题！我写了如下代码：代码1是去掉转义字符
代码2是增加转义字符
在测试的时候 我用了字符串 char text1[50] = "\aHello,\\n\n\tWorld! Mistakee\b was \"Extra 'e'\"!\\n";
结果输出不正常了！！不知道错在哪里，请坛子里的大神给指点下啊！
代码1：
程序代码：void escape(char *s,char *t){
int count = 0;
while( *t != '\0') {
switch( *t ) {
case '\n':
*(s + (count++) ) = '\\';
*(s + count ) = 'n';
break;
case '\t':
*(s + (count++) ) ='\\';
*(s + count ) = 't';
break;
case '\b':
*(s + (count++) ) = '\\';
*(s + count ) = 'b';
break;
case '\f':
*(s + (count++) ) = '\\';
*(s + count ) = 'f';
break;
case '\r':
*(s + (count++) ) = '\\';
*(s + count ) = 'r';
break;
case '\v':
*(s + (count++) ) = '\\';
*(s + count ) = 'v';
break;
case '\\':
*(s + (count++) ) = '\\';
*(s + count ) = '\\';
break;
case '\"':
*(s + (count++) ) = '\\';
*(s + count ) = '\"';
break;
default:
/* This is not a special character, so just copy it */
*(s + count ) = *t;
break;
}
count++ ;
t++;
}
*(s + count ) = *t ;
}代码2：
程序代码：void unescape(char *s,char *t ){
int count = 0;
while( *s != '\0') {
switch( *s ) {
case '\\':
switch ( *(++s) ){
case 'n':
*(t + count ) = '\n';
break;
case 't':
*(t + count ) = '\t';
break;
case 'b':
*(t + count ) = '\b';
break;
case 'f':
*(t + count ) = '\f';
break;
case 'r':
*(t + count ) = '\r';
break;
case 'v':
*(t + count ) = '\v';
break;
case '\\':
*(t + count ) = '\\';
break;
case '\"':
*(t + count ) = '\"';
break;
default:
*(t + (count++) ) = '\\';
*(t + count ) = *s;
break;
}
break;
default:
/* This is not a special character, so just copy it */
*(t + count ) = *s;
break;
}
count++ ;
s++;
}
*(t + count ) = *s ;
}代码3 测试：
程序代码：int main(){
char *s= "12132343245235426546qefwqefasdfwefasfwefasdfaseqefq";
char text1[50] = "\aHello,\\n\n\tWorld! Mistakee\b was \"Extra 'e'\"!\\n";
char *text2 = " ";
printf("%s\n",text1); /* 输出源串*/
escape( s,text1);
printf("%s\n",s); /* 输出取消转义字符之后的串*/
unescape( s,text2);
printf(" %s\n",text2);/* 输出增加转义字符之后的串*/
getch();
return 0;
}
[ 本帖最后由 erick8888 于 2015-6-23 14:46 编辑 ]
