定义一个基类Base，有两个公有成员函数fu1(),fu2()，私有派生出Derived类，如何通过Derived类的对象调用基类的函数fu1()。
#include<iostream>
using namespace std;
class Base
{
public:
    int fu1()
    {
        cout<<"Base func 1"<<endl;
        return 0;
    }
    int fu2()
    {
        cout<<"Base func 2"<<endl;
        return 0;
    }
};
class Derived:private Base{};
int main()
{
    Derived a;
    a.Base::fu1();
    return 0;
}
派生类的函数体和调用代码不知道怎么写啊？

class Derived:private Base
{
public:
    zi1(){cout<<"Derived func1\n";}//函数体根本就是随便你怎么写，或者你可以不写
};
int main()
{
    Derived a;
    a.fu1();//调用父类函数
    return 0;
}

有错误，这样不对的！
1>d:\c++语言程序设计\7-9\7-9\7-9.cpp(25) : error C2247: 'Base::fu1' not accessible because 'Derived' uses 'private' to inherit from 'Base'

正确解答：
#include<iostream>
using namespace std;
class Base
{
public:
    int fu1()
    {
        cout<<"Base func 1"<<endl;
        return 0;
    }
    int fu2()
    {
        cout<<"Base func 2"<<endl;
        return 0;
    }
};
class Derived:private Base
{
public:
    int fu1(){return Base::fu1();}
    int fu2(){return Base::fu2();}
};
int main()
{
    Derived a;
    a.fu1();//调用父类函数
    return 0;
}

换成公有继承看看

公有继承当然可以了，我要的就是私有继承的情况！

这样OK么？
#include<iostream>
using namespace std;
class Base{
    public:
        Base(){}
        ~Base(){}
        void fn1(){
            cout<<"fn1"<<endl;
        }
        void fn2(){
            cout<<"fn2"<<endl;
        }
};
class Derived:private Base{
    public:
        Derived(){}
        ~Derived(){}
        void lalala(){
            Base::fn1() ;
        }
};
int main(){
    Derived a;
    a.lalala() ;
    return 0;
}