定义一个枚举类型enum month描述1至12个月各用英文缩写表示，并且编写一个程序，使得输入一个年份，将这个年份的每个月的英文名全称以及月数输出。
我觉得这道题第一必须解决闰年平年问题，我使用了if else
可是枚举的Jan等月数，英文名怎么输出，实在不会。请各位高手帮忙
#include<stdio.h>
enum month { Jan, Feb, Mar, Apr, May, Jun, Jul, Aug, Sep, Oct, Nov, Dec };
int main()
{  int year;
   char *monthDetail1[]={"January 31","February 28","March 31","April 30","May 31","June 30","July 31","August 31","September 30","October 31","Novmber 30","Decmber 31"};
   char *monthDetail2[]={"January 31","February 27","March 31","April 30","May 31","June 30","July 31","August 31","September 30","October 31","Novmber 30","Decmber 31"};
   scanf("%d",year);
   if(!(year%4)&&year%100||!(year%400))
      printf("%s\n",monthDetail2);
    else
   printf("%s\n",monthDetail1);

   return 0;
   }

你确定没有打错字？

难道平年闰年的月数还不一样？

#include<stdio.h>

const char *m1[] = {"January 31", "February 28", "March 31", "April 30", "May 31", "June 30", "July 31", "August 31", "September 30", "October 31", "Novmber 30", "Decmber 31"};
const char *m2[] = {"January 31", "February 29", "March 31", "April 30", "May 31", "June 30", "July 31", "August 31", "September 30", "October 31", "Novmber 30", "Decmber 31"};

void prt(const char *m[]) {
    int i;
    for(i = 0; i < 12; i++)
        printf("%s\n", m[i]);
}

int main(void) {

    int year;
    
    scanf("%d", &year);

    if((0 == year % 4 && 0 != year % 100) || (0 == year % 400))
        prt(m2);

    else
        prt(m1);

    return 0;
}

不好意思。。。是每个月的天数。不一样

及日数。。。。

谢谢您，如果代码里有什么不懂的，我会询问您的！

假如说一定要用上枚举
可以这样

#include<stdio.h>

const char *m1[] = {"January 31", "February 28", "March 31", "April 30", "May 31", "June 30", "July 31", "August 31", "September 30", "October 31", "Novmber 30", "Decmber 31"};
const char *m2[] = {"January 31", "February 29", "March 31", "April 30", "May 31", "June 30", "July 31", "August 31", "September 30", "October 31", "Novmber 30", "Decmber 31"};

void prt(const char *m[]) {
    enum month { Jan, Feb, Mar, Apr, May, Jun, Jul, Aug, Sep, Oct, Nov, Dec };
    int i;
    for(i = Jan; i <= Dec; i++)
        printf("%s\n", m[i]);
}

int main(void) {

    int year;
    
    scanf("%d", &year);

    if((0 == year % 4 && 0 != year % 100) || (0 == year % 400))
        prt(m2);

    else
        prt(m1);

    return 0;
}

班长你好