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标题:关于单向循环链表
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gold615
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关于单向循环链表
刚开始看数据结构,自己写了几行,目的是输入两个未知长度大小的循环链表,然后把这两个 链表合并成一个新的循环链表。
但是执行的时候发现,第一个链表 可以完整的输入进去,每次一开始输入第二个链表就死机,找了半天也没有发现问题在哪里。求各位大神帮忙看看那个输入链表的子函数是不是有问题。
#include<stdio.h>
#include<malloc.h>
typedef struct node
{
    int a;
    node * next;
};
node *input_linked_list(node *head,int *count)//输入链表
{
    node *p,*last=NULL;
    char c='y';int i=1;
    while(1)
    {
        printf("please input the %d number:\t",i);
        p=(node *)malloc(sizeof(node));
        scanf("%d",&(p->a));getchar();
        if(head==NULL)
        {
            head=p;
        }
        else if(i==1)
        {
            head->next=p;
        }
        if(last==NULL)last=p;
        else
        {
            last->next=p;
            last=p;
        }
        (*count)++;i++;
        printf("continue? y&n\t");
        scanf("%c",&c);
        if(c=='n')
        {
            break;
        }
    }
    last->next=head;
    return last;
}
void print(node * link_head,node *link_last)
{
    node *p=link_head;
    while(p->next!=link_head)
    {
        printf("%d\t",p->next->a);
        p=p->next;
    }
    printf("\n");
}
void combine(node *last1,node * last2)
{
    node *temp;
    temp=last1->next;
    last1->next=last2->next;
    last2->next=temp;
}
main()
{
    node *head1,*head2,*last1,*last2;
    int count1=0,count2=0;
    printf("please input the first link.\n");
    last1=input_linked_list(head1,&count1);
    printf("the length of the first link is %d\n",count1);
    printf("the element is :\n");
    print(head1,last1);
    printf("please input the second link.\n");
    last2=input_linked_list(head2,&count2);
    printf("the length of the second link is %d\n",count2);
    combine(last1,last2);
    print(last1->next,last2->next);
    printf("\n");
}
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2015-01-07 23:37
gold615
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没人回么?
2015-01-08 11:02
bin17
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#include<stdio.h>
#include<malloc.h>

typedef struct node
{
    int a;
    struct node* next;
}node;
node *input_linked_list(int *count)//输入链表
{
    node *head,*p,*q;
    head = (node *)malloc(sizeof(node));
    head->next = NULL;
    p = head;
    char c='y';int i = 1;
    while(1)
    {
        printf("please input the %d number:\t",i++);
        q=(node *)malloc(sizeof(node));
        scanf("%d",&(q->a));getchar();
        q->next = NULL;
        p->next = q;
        p = p->next;
        (*count)++;
        printf("continue? y&n\t");
        scanf("%c",&c);
        if(c=='n')
        {
            break;
        }
    }
    q->next=head;
    return head;
}
void print(node * link_head)
{
    node *p=link_head;
    while(p->next!=link_head)
    {
        printf("%d\t",p->next->a);
        p=p->next;
    }
    printf("\n");
}
node* combine(node *head1,node * head2)
{
    node *p,*q;
    p =head1;
    q = head2;

    while(p->next!=head1)
    {
        p=p->next;
    }

    p->next = head2->next;

    while(p->next!=head2)
    {
        p=p->next;
    }
    p->next = head1;

    return head1;
}
main()
{
    node *head1,*head2,*last1,*last2;
    int count1=0,count2=0;
    printf("please input the first link.\n");
    head1 = input_linked_list(&count1);
    printf("the length of the first link is %d\n",count1);
    printf("the element is :\n");
    print(head1);
    printf("please input the second link.\n");
    head2=input_linked_list(&count2);
    printf("the length of the second link is %d\n",count2);
    print(head2);

    head1 = combine(head1,head2);
    print(head1);
 //   combine(last1,last2);
    printf("\n");
}
2015-01-08 21:30
ffbh
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第三行的typedef后面没写新的定义名
2015-01-15 21:21
快速回复:关于单向循环链表
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