public class T9 {
    public static void main(String [] args){
        Scanner in=new Scanner(System.in);
int n=in.nextInt()-1;
        String [] a={"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
        String [] A=new String[26];
        A[0]=a[0];
        for (int i = 1; i <A.length; i++) {//就是这里出了问题导致运行不了如果将A。length改小一点就可以运行
            A[i]=A[i-1]+a[i]+A[i-1];
        }
        System.out.println(A[n]);
        
    }
}
运行之后显示
Exception in thread "main" java.lang.OutOfMemoryError: Java heap space
    at java.util.Arrays.copyOf(Arrays.java:2367)
    at java.lang.AbstractStringBuilder.expandCapacity(AbstractStringBuilder.java:130)
    at java.lang.AbstractStringBuilder.ensureCapacityInternal(AbstractStringBuilder.java:114)
    at java.lang.AbstractStringBuilder.append(AbstractStringBuilder.java:415)
    at java.lang.StringBuilder.append(StringBuilder.java:132)
    at T9.main(T9.java:119)

你这里好像有错，循环那里有错，改成这个i=0或者i<=A.length看还会不会报错

StringBuffer或StringBuilder，可以存储大文本

LZ你的代码有问题啊  for (int i = 1; i <A.length; i++) {
            A[i]=A[i-1]+a[i]+A[i-1];
        }
当你的i=25的时候， A[i]里面存的字符串长度是2^25-1,你想想看内存能不溢出吗？

因为我A【0】已经给定了，所以我只要再输入25位就好了，然后A。length=26,从i=1开始就刚好25位啦

我真是服了你了,用字符串数组还一个一个字母赋值,你就不能用String a="kjdgfjdkshlgshgdls(写在这)";然后再用charAt(i)打出来啊?