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标题:小游戏、大家看看、代码居多。
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xiaqi77
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等 级:新手上路
帖 子:3
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注 册:2014-1-6
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小游戏、大家看看、代码居多。
代码太多、求优化、
求告知如何把这个游戏编译出来到其他电脑上使用。

以下代码:

#include <stdio.h>
#include <stdlib.h>
char sum[9] = {49,50,51,52,53,54,55,56,57};
void biao (char *psum)
{
     printf("   当前棋谱 : \n\n");
     printf("   %c | %c | %c\n",psum[0],psum[1],psum[2]);
     printf("  ---+---+---\n");
     printf("   %c | %c | %c\n",psum[3],psum[4],psum[5]);
     printf("  ---+---+---\n");
     printf("   %c | %c | %c\n\n",psum[6],psum[7],psum[8]);
}

void error()
{
    biao(sum);
    printf("此处已经被占领,请重试!\n");
}
char panduan(char *psum)
{
    if(psum[0]=='O'&&psum[1]=='O'&&psum[2]=='O'
    || psum[3]=='O'&&psum[4]=='O'&&psum[5]=='O'
    || psum[6]=='O'&&psum[7]=='O'&&psum[8]=='O'
    || psum[0]=='O'&&psum[4]=='O'&&psum[8]=='O'
    || psum[2]=='O'&&psum[4]=='O'&&psum[6]=='O'
    || psum[0]=='O'&&psum[3]=='O'&&psum[6]=='O'
    || psum[1]=='O'&&psum[4]=='O'&&psum[7]=='O'
    || psum[2]=='O'&&psum[5]=='O'&&psum[8]=='O')
       return 1;
    if(psum[0]=='X'&&psum[1]=='X'&&psum[2]=='X'
    || psum[3]=='X'&&psum[4]=='X'&&psum[5]=='X'
    || psum[6]=='X'&&psum[7]=='X'&&psum[8]=='X'
    || psum[0]=='X'&&psum[4]=='X'&&psum[8]=='X'
    || psum[2]=='X'&&psum[4]=='X'&&psum[6]=='X'
    || psum[0]=='X'&&psum[3]=='X'&&psum[6]=='X'
    || psum[1]=='X'&&psum[4]=='X'&&psum[7]=='X'
    || psum[2]=='X'&&psum[5]=='X'&&psum[8]=='X')
       return 2;
}

 int main()
 {
     kaishi :
     {
     char shuru;
     char *psum;
     char pd;
     int aa;
     psum = sum;
     printf("游戏规则,玩家输入相应序号即可.\n");
     biao(sum);
     char player1[30];
     char player2[30];
     printf("请输入玩家1的名字:");
     scanf("%s",player1);
     printf("请输入玩家2的名字:");
     scanf("%s",player2);
     int s = 1;
     int qi = 0;
     int win = 0;
     do{
     do{
         printf("轮到%s输入:",player1);
         scanf("%d",&qi);
         system("cls");
         switch(qi)
         {
            case 1 : if (sum[0] == 'O' || sum[0]=='X')
                         {error();continue;}
                     psum[0] = 'O'; break;
            case 2 : if (sum[1] == 'O' || sum[1]=='X')
                         {error();continue;}
                     psum[1] = 'O'; break;
            case 3 : if (sum[2] == 'O' || sum[2]=='X')
                         {error();continue;}
                     psum[2] = 'O'; break;
            case 4 : if (sum[3] == 'O' || sum[3]=='X')
                         {error();continue;}
                     psum[3] = 'O'; break;
            case 5 : if (sum[4] == 'O' || sum[4]=='X')
                         {error();continue;}
                     psum[4] = 'O'; break;
            case 6 : if (sum[5] == 'O' || sum[5]=='X')
                         {error();continue;}
                     psum[5] = 'O'; break;
            case 7 : if (sum[6] == 'O' || sum[6]=='X')
                         {error();continue;}
                     psum[6] = 'O'; break;
            case 8 : if (sum[7] == 'O' || sum[7]=='X')
                         {error();continue;}
                     psum[7] = 'O'; break;
            case 9 : if (sum[8] == 'O' || sum[8]=='X')
                         {error();continue;}
                     psum[8] = 'O'; break;
            default: printf("输入错误会导致程序崩溃!只能输入数字喔!\n");break;
         }
         biao(sum);
         s++;
     }while(s%2!=0);
     win = panduan(sum);
     if(win == 1) {printf("  恭喜! %s WIN!\n\n",player1); break;}
     do
     {
         printf("轮到%s输入:",player2);
         scanf("%d",&qi);
         system("cls");
         switch(qi)
         {
            case 1 :if (sum[0] == 'O' || sum[0]=='X')
                     {error();continue;}
                    psum[0] = 'X'; break;
            case 2 :if (sum[1] == 'O' || sum[1]=='X')
                        {error();continue;}
                    psum[1] = 'X'; break;
            case 3 :if (sum[2] == 'O' || sum[2]=='X')
                        {error();continue;}
                    psum[2] = 'X'; break;
            case 4 :if (sum[3] == 'O' || sum[3]=='X')
                        {error();continue;}
                    psum[3] = 'X'; break;
            case 5 :if (sum[4] == 'O' || sum[4]=='X')
                        {error();continue;}
                    psum[4] = 'X'; break;
            case 6 :if (sum[5] == 'O' || sum[5]=='X')
                        {error();continue;}
                    psum[5] = 'X'; break;
            case 7 :if (sum[6] == 'O' || sum[6]=='X')
                        {error();continue;}
                    psum[6] = 'X'; break;
            case 8 :if (sum[7] == 'O' || sum[7]=='X')
                        {error();continue;}
                    psum[7] = 'X'; break;
            case 9 :if (sum[8] == 'O' || sum[8]=='X')
                        {error();continue;}
                     psum[8] = 'X'; break;
            default :printf("输入错误! 会导致程序崩溃!只能输入数字喔!\n");break;
         }
         biao(sum);
         s++;
     }while(s%2==0);
     win = panduan(sum);
     if(win == 2) {printf("  恭喜! %s WIN!\n\n",player2); break;}
     }while(s<9);
     if(win!=1&&win!=2)
        printf("平局咯!请重新开始!\n\n");
        printf("是否继续 Y/N \n");
        scanf("%s",&shuru);
        if(shuru == 'Y' || shuru == 'y')
            goto kaishi;
        printf("游戏结束!\n");
     system("pause");
    return 0;
}}
搜索更多相关主题的帖子: 如何 小游戏 include 
2014-02-28 15:21
快速回复:小游戏、大家看看、代码居多。
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