请问：错在那里了？
程序代码：/*
（3）已知个人信息类Cperson的数据成员有姓名、年龄、性别、学号；
从类Cperson派生班级类CClass类，新增加数据成员有年级、班号、人数、班主任。
设计一个主函数实现显示派生类的有关信息。
*/
#include <iostream>
#include <string.h>
using namespace std;
//已知个人信息类Cperson的数据成员有姓名、年龄、性别、学号；
class cperson
{
private:
char name[30],sex,number;
double age;
public:
void set(char *n,double a,char s,char num)
{
strcpy(name,n);
age=a;
sex=s;
number=num;
}
void display()
{
cout<<"name:"<<name<<",age:"<<age<<",sex:"<<sex<<",number:"<<number<<endl;
}
};
//从类Cperson派生班级类CClass类，新增加数据成员有年级、班号、人数、班主任。
class cclass:public cperson
{
private:
char grade,class_,people,headmaster[30];
public:
void set(char *n,double a,char s,char num,char g,char c,char p,char *h)
{
cperson::set(*n,a,s,num);
strcpy(headmaster,h);
grade=g;
class_=c;
people=p;
}
void display()
{
cperson::display();
cout<<"Grade:"<<grade<<",class:"<<class_<<",number of people:"<<people<<",headmaster:"<<headmaster<<endl;
}
};
void main()
{
cclass p;
p.set("Wang Ming",18,"f","12315","grade 2","class 8","110","Liang Dongqiang");
p.display();
}
错误：
--------------------配置: vc6.0 - CUI Debug, 编译器类型: Microsoft C++ Compiler--------------------
检查文件依赖性...
正在编译 C:\Users\by_stro\Documents\C-Free\Temp\未命名2.cpp...
未命名2.cpp
[Error] C:\Users\by_stro\Documents\C-Free\Temp\未命名2.cpp:36: C2664: 'set' : cannot convert parameter 1 from 'char' to 'char *'
Conversion from integral type to pointer type requires reinterpret_cast, C-style cast or function-style cast
[Error] C:\Users\by_stro\Documents\C-Free\Temp\未命名2.cpp:51: C2664: 'set' : cannot convert parameter 3 from 'char [2]' to 'char'
This conversion requires a reinterpret_cast, a C-style cast or function-style cast
构建中止 未命名2: 2 个错误, 0 个警告
