#include "stdafx.h"
#include "stdio.h"


main(){
    static char *name[]={ "Illegal day",
        "Monday","Tuesday","Wednesday",
        "Thursday","Friday","Saturday",
        "Sunday"};
    char *ps;
    int i;
    char *day_name(char *name[],int n);
    printf("input Day No:\n");
    scanf("%d,&i");
    if(i<0)  exit(1);
    ps=day_name(name,i);
    printf("Day No:%2d-->%s\n",i,ps);
}
char *day_name(char[],int n)
{
    char *pp1,*pp2;
    pp1=*name;
    pp2=*(name+n);
    return((n<1||n>7)?pp1:pp2);
}

scanf("%d,&i");

:\Program Files\Microsoft Visual Studio\7\7.cpp(18) : error C2065: 'exit' : undeclared identifier
C:\Program Files\Microsoft Visual Studio\7\7.cpp(21) : warning C4508: 'main' : function should return a value; 'void' return type assumed
C:\Program Files\Microsoft Visual Studio\7\7.cpp(25) : error C2065: 'name' : undeclared identifier
C:\Program Files\Microsoft Visual Studio\7\7.cpp(25) : error C2100: illegal indirection
C:\Program Files\Microsoft Visual Studio\7\7.cpp(25) : error C2440: '=' : cannot convert from 'int' to 'char *'
        Conversion from integral type to pointer type requires reinterpret_cast, C-style cast or function-style cast
C:\Program Files\Microsoft Visual Studio\7\7.cpp(26) : error C2100: illegal indirection
C:\Program Files\Microsoft Visual Studio\7\7.cpp(26) : error C2440: '=' : cannot convert from 'int' to 'char *'
        Conversion from integral type to pointer type requires reinterpret_cast, C-style cast or function-style cast
执行 cl.exe 时出错.

7.exe - 1 error(s), 0 warning(s)
还有这个。。。。。。。

输入部分错了

改了还是那样

个人理解：

char *day_name(char[],int n)//红色部分不懂


 pp1=*name;红色部分似乎没有申明

学习。。我都忘光了。。

 #include "stdio.h"


 main(){
     static char *name[]={ "Illegal day",
         "Monday","Tuesday","Wednesday",
         "Thursday","Friday","Saturday",
         "Sunday"};
     char *ps;
     int i;
     char *day_name(char *name[],int n);
     printf("input Day No:\n");
     scanf("%d",&i);
     if(i<0)  exit(1);
     ps=day_name(name,i);
     printf("Day No:%2d-->%s\n",i,ps);
 }
 char *day_name(char *name[],int n)
 {
     char *pp1,*pp2;
     pp1=*name;
     pp2=*(name+n);
     return((n<1||n>7)?pp1:pp2);
 }