#include <iostream>

struct job
{
    char name [40];
    double salary;
    int floor;
};

template <> void Swap<job>(job &j1,job &j2);



int _tmain(int argc, _TCHAR* argv[])
{

   ......
   ......
    return 0;
}
template <> void Swap <job> (job &j1,job &j2)
{
    double t1;
    int t2;
    t1 = j1.salary;
    j1.salary = j2.salary;
    j2.salary = t1;

    t2 = j1.floor;
    j1.floor = j2.floor;
    j2.floor = t2;

}
请问下各位大神，这里函数原型时，用模板和不用模板  有什么具体区别呢？？
template <> void Swap<job>(job &j1,job &j2);
我改成  void Swap (job &j1,job &j2);不是一样么？？