#include <stdio.h>


int monthdays[12]={31,28,31,30,31,30,31,31,30,31,30,31};

int leapyearmonthdays[12]={31,29,31,30,31,30,31,31,30,31,30,31}; int year=2011; int month=4; int day=22;

int isweekday(int y,int m,int d) {

int weekday; if(m<3) {

m+=12; y--; }

return weekday=(2+2*m+3*(m+1)/5+y+y/4-y/100+y/400)%7; }

int isleapyear(int y) {

if (y%400==0 || y%100!=0 && y%4==0) return 1; return 0; }

void print_month(int y,int m) {

int i=0;

int startday=isweekday(y,m,1); printf("\n%4d/%02d\n",y,m);

printf("*****************************\n"); for(i=0;i<startday;i++) {

printf(" "); }

if(isleapyear(y)) {

for(i=1;i<=leapyearmonthdays[m-1];i++) {

printf("%3d ",i); if((startday+i)%7==0) printf("\n"); }

} else {

for(i=1;i<=monthdays[m-1];i++) {

printf("%3d ",i); if((startday+i)%7==0) printf("\n"); } }

printf("\n*****************************\n"); }

void print_year(int y) {

int i;

for(i=1;i<=12;i++)

{

print_month(y,i); } }

int counterdays(int y,int m,int d) {

int temp=0; int days=0; int i;

for(i=year+1;i<y;i++) {

if(isleapyear(i)) temp++; }

if(y-year>=1) {

if(isleapyear(year) && month<=2) temp++;

if(isleapyear(y) && m>2 ||(m==2 && d==29)) temp++;

for(i=month+1;i<=12;i++) {

days+=monthdays[i-1]; }

for(i=1;i<m;i++) {

days+=monthdays[i-1]; }

days+=(y-year-1)*365; }

if(!(year==y && month==m)) {

days+=monthdays[month-1]-day+d; } else {

days+=d-day; }

days+=temp;

printf("\n今天距%d/%d/%d还有%d天\n",y,m,d,days);

return days; }


void setday(int y,int m,int d) {

year=y; month=m; day=d; }

void main() {

int temp; int y,m,d; char ch; do{

printf("请输入要查询的方式(1.查询年历2.查询月历3.计算日期4.设置当前日期(%d/%d/%d)):",year,month,day); scanf("%d",&temp); switch(temp) {

case 1:

printf("请输入年份(ep:2011):"); scanf("%d",&y); print_year(y); break; case 2:

printf("请输入年月(ep:2011/4):"); scanf("%d/%d",&y,&m); print_month(y,m); break; case 3:

printf("请输入日期(ep:2011/4/22):"); scanf("%d/%d/%d",&y,&m,&d); counterdays(y,m,d); break; case 4:

printf("请输入当天日期(ep:2011/4/22):"); scanf("%d/%d/%d",&y,&m,&d); setday(y,m,d); break;

default: break; }

printf("\n\n是否继续？(Y键继续,任意键退出)"); getchar();

scanf("%c",&ch);

}while(ch=='y' || ch=='Y'); }
大神帮忙看一下

这是我写的一个日历，看看对你有没有帮助

谢谢你，问题已解决了。