#include <stdio.h>

int main()

 {
     int i=2,j=1,sum;
     for(;i<=1000;i++)
     {
         sum=0;
         for(j=1;j<i;j++)
             if((i%j)==0)
                 sum=sum+j;
             if(i==sum)
             {
                 printf("%d its factors are");
                 for(j=1;j<i;j++)
                     if((i%j)==0)
                         printf(" %d",j);
                     printf("\n");
             }
     }
     return 0;
 }

程序本身没什么错吧应该，但结果有部分数据很奇怪，不知是否为电脑问题，大家可以复制并看看结果。

谢谢。

printf("%d its factors are");改成printf("%d its factors are", i);

呵呵  小错误   该注意

这个我也敲过。。。# include <stdio.h>
main()
{
    int sum,i,n;
    for(n = 2;n<1000;n++)
    {
        
        sum = 0;
        for(i = 1;i<n;i++)
        {
            if(n%i==0)
            {
                sum = sum + i;
            }
        }
        if(sum==n)
        {
            printf("\n%d its are ",sum);
            for(i = 1;i<n;i++)
            {
                if(n%i==0)
                {
                    printf("%d, ",i);
                }
            }
        printf("\n");
        }

    }
}

#include <stdio.h>
 
int main()
 
{
      int i=2,j=1,sum;
      for(;i<=1000;i++)
      {
          sum=0;
          for(j=1;j<i;j++)
              if((i%j)==0)
                  sum=sum+j;
              if(i==sum)
              {
                  printf("%d its factors are",i);//这里有个小错误，你要输出的值i没写出来
                  for(j=1;j<i;j++)
                      if((i%j)==0)
                          printf(" %d",j);
                      printf("\n");
              }
      }
      return 0;
 }
 

int main() 这个括号里面不用 void 吗？

for(;i<=1000;i++)里面多了个;

那个冒号没有多哦亲！

那个冒号没有多

7楼就够奇葩的了，8楼更逗，居然说冒号