#include<stdio.h>
char swap(char *words1,char *words2);
main()
{
    char *arr,*arry;
    char c[]="aChina";
    char put[5];
    for(arr=c,arry=put;arr<(c+5);arr++,arry++){
        swap(arr,arry);
        printf("%s\n",*arry);
    }
}
char swap(char *words1,char *words2)
{
    *words2=*words1+4;
    return *words2;
}

#include<stdio.h>
#include<stdlib.h>
 void swap(char *words1,char *words2);
int main(void)
 {     
         char c[]="aChina";
     char put[5];
     char *arr=c,*arry=put;
     
     
         swap(arr,arry);
         printf("%s\n",arry);
     
     system("pause");
     return 0;
 }
 void swap(char *words1,char *words2)
 {for(int i=0;i<5;++i)
 {
     *(words2+i)=*(words1+i)+4;
     
        }
 }
//

学习下，好神奇。

2楼的程序貌似有问题，明天再说吧，宿舍快停电了

宿舍还 停电？

输出单个字符？用%c吧。

楼主把题意说具体下呗

#include<stdio.h>
char swap(char *words1,char *words2,int n);//增加个n控制*(words1+n)，防止数组越界
int main()
{
    int num;//为了得到作为n的实参的值而存在
    char *arr,*arry;
    char c[]="aChina";
    char put[6]={'0'};//楼主给数组长度为5，这里最好赋初值并且多申请一个空间放结束标志'\0'
    put[6]='\0';//这是告诉char指针结束
    for(arr=c,arry=put,num=0;arr<(c+5);arr++,arry++,num+=2)
    {
        swap(arr,arry,5-num);//给传5-num是控制*(words1+n)在合理范围内
        printf("%s\n",arry);//用%s输出char指针类型，就不用加*了，给指针的首地址就行
    }
    return 0;
}
char swap(char *words1,char *words2,int n)
{
    *words2=*(words1+n);
    return *words2;
}

//我理解的楼主的意思是让*arr中的值倒着输出……